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Llana [10]
3 years ago
11

When comparing the reaction rates for the SN2 substitution of two alkyl halides, the more hindered substrate will undergo substi

tution _________ (correct answer is "faster" or "more slowly") than the less substituted substrate.
Chemistry
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

The more hindered subtrate will undergo substitution more slowly than the less substituted substrate.

Explanation:

The <em>SN2 substitution reaction rate</em> is affected by four factors:

  1. The substrate. The more substituted the substrate, the slower the reaction.
  2. The nucleophile. The stronger the nucleophile the faster the reaction.
  3. The solvent. Polar aprotic solvents do not hinder the reaction, as opposed to polar protic solvents.
  4. The leaving group. The better the leaving group (stability and bond strength), the faster the reaction.
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FrozenT [24]
C. The neutron number.

An element is determined based on how many protons has, if the protons number change then you got a new element.

If the number of neuron change you got the same element except it will be a bit heavier or lighter if you are gaining or loosing neutrons. Those variations of an element are called the isotops of the element.

The protons and neutrons toghether form the nucleus of the atom that is heavy and dense as an elephant.

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3 years ago
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3. Find the mass of 4.77 x 1022 atoms of scandium<br> (Sc).
iren2701 [21]

Answer:

Mass = 3.6 g

Explanation:

Given data:

Number of atoms of scandium = 4.77×10²² atoms

Mass of arsenic = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022× 10²³ is called Avogadro number.

one mole =  6.02×10²³ atoms

one mole × 4.77×10²² atoms / 6.02×10²³ atoms

0.08 mol

Mass of scandium

Mass = number of moles × molar mass

Mass = 0.08 mol ×  45 g/mol

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7 0
3 years ago
Making the simplistic assumption that the dissolved NaCl(s) does not affect the volume of the solvent water, determine the const
shtirl [24]

Answer:

  • m = 1,000/58.5
  • b = - 1,000 / 58.5

1) Variables

  • molarity: M
  • density of the solution: d
  • moles of NaCl: n₁
  • mass of NaCl: m₁
  • molar mass of NaCl: MM₁
  • total volume in liters: Vt
  • Volume of water in mililiters: V₂
  • mass of water: m₂

2) Density of the solution: mass in grams / volume in mililiters

  • d = [m₁ + m₂] / (1000Vt)

3) Mass of NaCl: m₁

    Number of moles = mass in grams / molar mass

    ⇒ mass in grams = number of moles × molar mass

        m₁ = n₁ × MM₁


4) Number of moles of NaCl: n₁

   Molarity = number of moles / Volume of solution in liters

   M = n₁ / Vt

   ⇒ n₁ = M × Vt


5) Substitue in the equation of m₁:

   m₁ = M × Vt × MM₁


6) Substitute in the equation of density:

    d = [M × Vt × MM₁ + m₂] / (1000Vt)


7) Simplify and solve for M

  • d = M × Vt × MM₁ / (1000Vt) + m₂/ (1000Vt)
  • d = M × MM₁ / (1000) + m₂/ (1000Vt)

Making the simplistic assumption that the dissolved NaCl(s) does not affect the volume of the solvent water means 1000Vt = V₂  

  • d = M × MM₁ / (1000) + m₂/ V₂

        m₂/ V₂ is the density of water: 1.00 g/mL

  • d = M × MM₁ / (1000) + 1.00 g/mL
  • M × MM₁ / (1000) = d - 1.00 g/mL
  • M = [1,000/MM₁] d - 1,000/ MM₁

8) Substituting MM₁ = 58.5 g/mol

  • M = [1,000/58.5] d - [1,000/ 58.5]

Comparing with the equation Molarity = m×density + b, you obtain:

  • m = 1,000/58.5
  • b = - 1,000/58.5
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Valence.

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