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Llana [10]
4 years ago
11

When comparing the reaction rates for the SN2 substitution of two alkyl halides, the more hindered substrate will undergo substi

tution _________ (correct answer is "faster" or "more slowly") than the less substituted substrate.
Chemistry
1 answer:
zhuklara [117]4 years ago
8 0

Answer:

The more hindered subtrate will undergo substitution more slowly than the less substituted substrate.

Explanation:

The <em>SN2 substitution reaction rate</em> is affected by four factors:

  1. The substrate. The more substituted the substrate, the slower the reaction.
  2. The nucleophile. The stronger the nucleophile the faster the reaction.
  3. The solvent. Polar aprotic solvents do not hinder the reaction, as opposed to polar protic solvents.
  4. The leaving group. The better the leaving group (stability and bond strength), the faster the reaction.
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Given the solubility, calculate the solubility product constant (ksp) of each salt at 25°c: (a) pbcro4, s = 4.0 × 10−5 g/l; (b)
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a) PbCrO4:

according to the equation:

PbCrO4(s)  →  Pb2+(aq)   +  CrO42-(aq)

so, Ksp = [Pb2+][CrO42-]

by assuming [Pb2+] = [CrO42-] = X

and when S (the solubility) = 4 x 10^-5 g/L

we have first to convert solubility from g/L to mol/L by getting the molar mass of the salt 

solubility mol/L =  solubility g/L / molar mass of salt

                           = 4 x 10^-5g/L / 323.2 g/mol

                            = 1.24 x 10^-7 mol / L

by substitution in Ksp formula:

∴Ksp = X* X

         = (1.24 x 10^-7)^2

         = 1.54 x 10^-14

b) BaC2O4:

according to this equation:

BaC2O4(s)→  Ba 2+(aq)  +  C2O4 2- (aq)  

So Ksp = [Ba2+][C2O42-]

Assume that [Ba2+] = [C2O42-] = X

when the solubility S =  0.29 g/L = X  , so we need to convert S from g/L to
mol / L 

solubility mol / L= solubility g/L / molar mass of salt

                           = 0.29 g/L / 225.34 g/mol

                           = 0.0013 mol/L

by substitution in ksp formula:

∴Ksp = X^2 

         = (0.0013)^2 

         = 1.69 x 10^-6 

C)  MnCO3: 

according to this equation :

MnCO3(s)→ Mn2+(aq)   +  CO3 2-(aq)

so, Ksp = [Mn2+][CO32-]

assume [Mn2+] = [CO32-] = X

when the solubility s = 4.2 x 10^-6 g/L so we need to convert S from g/L to mol/L by dividing on molar mass.

the solubility mol/L = solubility g/L / molar mass g/mol

                                 =.4.2 x 10^-6 /114.9 

                                 = 3.7 x 10^-8 mol/L

by substitution on ksp formula:

∴ Ksp = X*X

           = (3.7 x 10^-8)^2

           = 1.369 x 10^-15
6 0
3 years ago
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