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fiasKO [112]
3 years ago
15

Write 42.638 in expanded form using fractions

Mathematics
1 answer:
stiks02 [169]3 years ago
6 0

Answer:

Expanded form or expanded notation is a way of writing numbers to see the math value of individual digits. When numbers are separated into individual place values and decimal places they can also form a mathematical expression. 5,325 in expanded notation form is 5,000 + 300 + 20 + 5 = 5,325.

Step-by-step explanation:

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Find the least common denominator between the two fractions. 1/4 and 3/5
zheka24 [161]
To Find the least common denominator you have to find the multiples of each number

multiple means the product of each factor

so the multiples of 4 would be 4 8 12 16 20

you want to name at least five multiples but if there are not the same multiples you might have to list more

the multiples of 5 would be 5 10 15 20

then I can stop there because I have found two of the same multiples

so now we have our least common denominator which is 20

HOPE THIS HELPS!!!
6 0
3 years ago
20 points<br> How on Earth am I supposed to do this
goblinko [34]

Answer: -89

Step-by-step explanation:

So your equation is

- 9(a) - 7(x) - 9(c) - 9(b) - 7(y)

You know that (a) (b) and (c) = -1

You also know that (x) and (y) = 7

So, when you put this into the equation, it will look like this:

- 9(-1) - 7(7) - 9(-1) - 9(-1) - 7(7)

When you work that out you will get left with your answer, which is -89.

HOPE THIS HELPS!!!

3 0
3 years ago
Help me please! Ommfhdhs
Klio2033 [76]
I don’t think I know but have a good day
3 0
3 years ago
Which expression represents the phrase below?
cestrela7 [59]

Answer:

B

Step-by-step explanation:

The number is x and you want 6 of that, so that makes 6x

You want 8 less of this, so subtract 8

Therefore you get 6x - 8

3 0
2 years ago
Read 2 more answers
Help me solve these equations
boyakko [2]

\left\{\begin{array}{ccc}3x-7y=20&|\cdot10\\11x+10y=5&|\cdot7\end{array}\right\\\underline{+\left\{\begin{array}{ccc}30x-70y=200\\77x+70y=35\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\\\.\ \ \ \ \ 107x=235\ \ \ \ |:107\\.\ \ \ \ \ \ \ \ \ \ x=\dfrac{235}{107}\\\\\text{substitute the value of x to the second equation}\\\\11\cdot\dfrac{235}{107}+10y=5\\\\\dfrac{2585}{107}+10y=\dfrac{535}{107}\ \ \ \ |-\dfrac{2585}{107}\\\\10y=-\dfrac{2050}{107}\ \ \ \ |:10\\\\y=-\dfrac{205}{107}

Answer:\ x=\dfrac{235}{107},\ y=-\dfrac{205}{107}

6 0
3 years ago
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