Answer:
Step-by-step explanation:
The velocity of the arrow when it was launched upwards is 320 feet per second. The height of the platform from which it was launched is 50 ft
This means that the arrow is already 50 feets from the ground before moving upwards.
The height that it attains on moving from 50 feets will be determined by Newton's formula of motion.
v^2 = u^2 + 2as
u = initial velocity = 320 feet per second.
1 feet per second = 0.305 meters per second
320 feet per second = 320× 0.305
= 97.6 feets per second
a = acceleration due to gravity =
- 32.17405 feet/second^2 because the arrow is moving upwards)
s =maximum height of the arrow
v = final velocity = 0 feet/second
Substituting into the equation,
0^2 = 97.6^2 + 2×- 32.17405 × s
0 = 9525.76 - 64.3481s
64.3481s = 9525.76
s = 9525.76/64.3481 = 148.03 feets
Total height from the ground would be
148.03 + 50 = 198.03 feets
Answer:
2(2/5x+2)=4x/5+4
Step-by-step explanation:
2(2/5x+2)=4x/5+4
4x/5 +4=4x/5 +4
The answer: 7 * 1,829 = " 12,803 " .
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<span>The following is the explanation—"in expanded form" — (as per the specfic instructions— within this very question—as to how to get the answer:
</span>____________________
Given: 7 * 1,829 = ? ; Find the solution; using "expanded form" :
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(7 * 9 = 63 ) ; +
(7 *20 = 140) ; +
(7 * 800 = 5,600) ; +
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(7 * 1,000 = 7,000) ;
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Now, add the the values together to solve the problem:
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→ 7 * 1,829 = 63 + 140 + 5,600 + 7,000 ;
{ = 203 + 5,600 + 7,000 } ;
{ = 5,803 + 7,000 } ;
= 12,803 ; which is the answer.
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Alternately, write out the steps as follows—using "expanded form":
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→ 7 * 1,829 = ?
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→ 7 * 1,829 = (7*9) + (7*20) + (7*800) + (1,000) ;
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→ 7 * 1,829 = 63 + 140 + 5,600 + 1,000 ;
{ = 203 + 5,600 + 7,000 } ;
{ = 5,803 + 7,000 } ;
= 12,803 ; which is the answer.
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→ {Now, is our obtained answer: "12,803" ; the "correct answer"—to the problem: " 7 * 1,829 " ;} ??
→ Let us check: {Note: " 7 * 1,829 " ; is the same as: ↔ " 1,829 * 7 " .}.
→ Using a calculator, does: "7 * 1829 = ? 12,803" ?? ; Yes! ;
→ &, for that matter; does: " 1829 * 7 =? 12,803" ?? ; Yes! .
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Furthermore, let us check, using the "traditional format" ;
→ Does: "1,829 * 7 =? 12,803 ?? " ;
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{NB: We are multiplying 2 (TWO) numbers together; & 1 (ONE) of these 2 [TWO] numbers is a "1-digit" ["single-digit"] number; & the "OTHER" multiplicand is a "multiple-digit" [specifically, a"4-digit"] number.}.
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NB: Yes; using a calculator is sufficient. Below, I simply provide an alternate method to confirm whether our "obtained value" is correct.
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→ Does: "7 * 1,289 = ? 12,803" ?? ;
→ Using the "traditional method"; let us check; as follows:
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₅ ₂ ₆
→ 1, 829
<span> <u> * 7 </u> </span>
12 8 03 ;
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So; does: "12,803 =? 12,803" ?? ; YES!
→ This "traditional method" shows that: "7 * 1,829" ; does, in fact, equal: "12,803".
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{NB: Explanation of the steps used in solving the aforementioned problem using the "traditional method"—just for clarification and confirmation} :
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→Start with: "7*9= 63" ; Write down the "3" & 'carry over' the "6" ; {Note the small-sized digit, "6"; written on top of the "2"; {commonly done—to keep track);
→Then; "7*2 = 14" ; then add the "small digit 6"; to the "14" ; →"14+6 =20" ;
Write down the "0" ; & 'carry over' the "2" ; {Note the "small-sized digit, "2"; written over the "8"; (commonly done—to keep track);
→ Then; "7*8 = 56" ; then add the "small digit 2"; to the "56"; → "56+2 = 58" ; Write down the "8" ; & 'carry over' the "5" ; {Note the "small-sized digit", "5" ; written over the "1" ; (commonly done—to keep track);
→Then; "7*1 = 7" ; then add the "small digit 5"; to the "7" ; → "7+5 = 12" ; Write down the "12" ; in its entirety—since are no digits left [in the multiplicand, "1,829"] ; to "carry over".
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We get: "12,803" ; which =? "12,803" ?? ;→Yes!
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I hope my explanation of how to solve "7 * 1,829" ; using the "expanded form" is helpful. Also, i hope my explanation—albeit lengthy— of confirming that [<em>our</em>] "correctly obtained value"—which is: "12,803"— is of some help.
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