<span>Hello : let
A(-3,7) B(3,3)
the slope is : (YB - YA)/(XB -XA)
(3-7)/(3+3) = -2/3
an equation is : y=ax+b a is a slope</span>
y = (-2/3)x +b
the line through point B (3,3) :
3 = (-2/3)(3)+b<span>
<span>b =5
the equation is : y =(-2/3)x+5</span></span>
Answer:
30+75x
Step-by-step explanation:
Answer:
15 girls
Explanation:
We know that the ratio of boys to girls in the classroom is 2:3, meaning that for every 2 boys there are 3 girls.
Now, we can set up a proportion to solve this problem.
Please see the picture attached.
I hope this helps!
see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
Answer:
70/3
Step-by-step explanation:
- Multiply: 23*3
- 23*3=69
- Add: 69+1
- 69+1=70
- 70/3
<em>Hope this helped!! :)</em>
<em>Brainliest?!?!</em>
<em>Stay safe and have a wonderful day/afternoon/night!!!</em>