Answer: Identify the shapes you will need to determine the area of the figure.
Calculate and add the areas of the unshaded triangle and two circles.
Step-by-step explanation:
Answer:
yeah it's blurry ¯\_(ツ)_/¯
Volume of reg sq. pyramid = vp
vp = 1/3×s^2×h, where s = side and h = height
Volume of cone = vc =1/3×h×pi×r^2
Now we know that h is the same for both, and the cones diameter = s of square base, so radius (r) = 1/2 s
so now vc = 1/3×h×pi×(1/2s)^2
let's remove the same items for both vc and vp
so 1/3 and h
now let's plug an arbitrary number into each:
vc = pi (10/2)^2 = 3.14×25 = 78.54
vp = s^2 = 10^2 = 100
So any square pyramid has slightly more volume than the cone
Using the equations for tangent and secant lines:
Let the unknown length of the line inside the circle = y
6^2 = 3 x (y+3)
Simplify:
36 = 3y+9
Subtract 9 from both sides:
27 =3y
Divide both sides by 3:
Y = 9
Now add to get x:
X = 9 + 3 = 12
X = 12
The absolute value of 4/13 is 4/13 because when you put something in absolute value it becomes positive and sense this is already positive it stays. hope this helps :))))
