9514 1404 393
Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
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1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
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3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
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5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
You will need to add 3 to each side.
x^2-3=15
+3 +3
x^2=12
and go from there
Answer:
The solution is:
![-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}](https://tex.z-dn.net/?f=-7r-4%5Cge%20%5C%3A%5C%3A4r%2B2%5Cquad%20%5C%3A%3A%5Cquad%20%5C%3A%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-0.54545%5Cdots%20%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%5C%3A%2C%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5D%5Cend%7Bbmatrix%7D)
Please check the attached line graph below.
Step-by-step explanation:
Given the expression
Add 4 to both sides
Simplify
Subtract 4r from both sides
Simplify
Multiply both sides by -1 (reverses the inequality)
Simplify
Divide both sides by 11
Simplify
Therefore, the solution is:
Please check the attached line graph below.
Answer:
(d) there is not enough information to tell if this is a biased sampling method.
Step-by-step explanation:
Based on reviews we cannot conclude whether the sampling is biased or not, if only we can know the total number of times the taxi was ordered then we can conclude.
When you graph an equation, it should be dependent variable against the independent variable. For this problem, the independent variable is the time, so this is along the x-axis. The dependent variable is d, so this is along the y-axis. Since the slope is Δy/Δx, then it is also equivalent to Δd/Δt. Therefore, the answer is B.
