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iragen [17]
4 years ago
7

Find a cubic polynomial in standard form with real​ coefficients, having the zeros 4 and 5i. Let the leading coefficient be 1.

Mathematics
1 answer:
SCORPION-xisa [38]4 years ago
3 0
If one of our zeros is 4, then the factor is x-4.  If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i.  So our 3 factors are (x-4)(x+5i)(x-5i).  We will FOIL out these factors to get the polynomial.  Let's start with the ones that contain the imaginary numbers.  Doing that mutliplication we get x^2-25i^2.  i^2 is equal to -1, so what that expression simplifies down to is x^{2} +25.  Now we will multiply in that last factor of (x-4):  (x^2+25)(x-4).  FOILing out we have x^3-4x^2+25x-100.  There you go!
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A vehicle factory manufactures cars. The unit cost (the cost in dollars to make each car) depends on the number of cars made. If
Nataly [62]

Answer:

The function is missing in the question. The function is $ C(x) = 0.8x^2 -544x +97410 $

The answer is 4930

Step-by-step explanation:

Unit cost of a car is given as

$ C(x) = 0.8x^2 -544x +97410 $

Cost will be minimum when

x = -(-544)/ 2 x 0.8

  = 340

Therefore, minimum cost for unit car is

$ C(x) = 0.8x^2 -544x +97410 $

$ = 0.8(340)^2 -544(340) +97410 $

=  4930

4 0
3 years ago
What is the volume of a rectangular prism with the following dimensions
andriy [413]

Answer: 250ft3

Step-by-step explanation:

v=l*w*H

v= 10*5 * 5

v=250

7 0
4 years ago
Read 2 more answers
Add together 2350mm 3.42cm 11/2m and 1.45m
Artyom0805 [142]
9.3342meters because you convert 2350mm into m which is 2.35m, + and also convert 3.42cm to m which is 0.0342 then + 1.45m +11/2m= 9.3342m
6 0
3 years ago
23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r
Nostrana [21]

Answer:

a) p_v =P(Z          

b) Since p_v we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) P(\bar X >90)=1-P(Z

1-P(Z

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}

And if we solve for n we got:

n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

We can calculate the sample mean and deviation with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

\bar X=88.96 represent the sample mean    

s=1.011 represent the sample standard deviation  

n=5 represent the sample selected  

\alpha significance level    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:    

Null hypothesis:\mu \geq 90    

Alternative hypothesis:\mu < 90    

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907      

Part a

P-value  

First we need to calculate the degrees of freedom given by:

df=n-1=5-1 = 4

Then since is a left tailed test the p value would be:    

p_v =P(Z    

Part b

Since p_v we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >90)=1-P(Z

1-P(Z

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}

And if we solve for n we got:

n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3

7 0
3 years ago
Factor x^3+3x^2+2x completely
Arisa [49]

Answer:

x^3 + 3x^2 + 2x = x(x^2 + 3x + 2)

= x(x^2 + x + 2x + 2)

= x(x(x+1) + 2(x+1))

=x(x+1)(x+2)

Hope this helps!

5 0
3 years ago
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