The area of the field where the length of each side is increased by 10% is 48.4
.
Step-by-step explanation:
The given is,
A rectangle field has an area of 40 
If one side of the field is 3 cm longer than the other side
The length of new area in each side is increased by 10%
Step:1
Let,
- One side of rectangle
- Other side of rectangle
From given.
-
+3
Formula for area of rectangle,
40 = ( b+3) × b
40 =
+ 3b
Solving the above the equation,
b = 5 cm
l = 8 cm
Step:2
If the area of rectangle increased by 10%,
l = 8 + ( 8 ×
)
= 8.8
b = 5 + ( 5 ×
)
= 5.5
Area of rectangle is,
a = ( 8.8 × 5.5 )
= 48.4 square centimeters
Result:
The area of the field where the length of each side is increased by 10% is 48.4
, if a rectangle field has an area of 40 square centimeters and one side of the field is 3 cm longer than the other side.
In fraction that would be 3/4 because 15/20 simplified would be three quarters.
If thats not the answer, message me back and I will go out of my way to figure out the correct one. Thats my policy :)
Answer:
is it B ?
Step-by-step explanation:
i think this is it y=3x+10 y = 3 x + 10. Use the slope-intercept form to find the slope and y-intercept.
Answer:
x = 6 sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
6^2+ x^2 = 12^2
36 + x^2 = 144
Subtract 36 from each side
x^2 = 144-36
x^2 =108
Take the square root of each side
sqrt(x^2) = sqrt(108)
x = sqrt(36*3)
x = 6 sqrt(3)
The best I can do is determine the roots:
3.5 plus 3.5707 i and
3.5 minus 3.5707 i