Using the polynomials Q = 3x 2 + 5x - 2, R = 2 - x 2, and S = 2x + 5, perform the indicated operation: Q - [R + S]

2 answers:

5 0

(3x^2+5x-2)- ((2-x^2+2x+5))
(3x^2+5x-2)- ((7-x^2+2x))
Since no more can be added or broken down
3x^2+5x-2 - 7-x^2+2x
2x^2+7x-9

nikitadnepr [17]3 years ago

4 0

Answer:

$4x^2+3x-9$

Step-by-step explanation:

Given the polynomials:

$Q = 3x^2+5x-2$

$R = 2-x^2$

$S = 2x+5$

We have to perform the indicated operation Q - [R + S]

$Q - [R + S] = 3x^2+5x-2-[2-x^2+2x+5]$

⇒ $Q - [R + S] = 3x^2+5x-2-2+x^2-2x-5$

Combine like terms;

⇒ $Q - [R + S] = 4x^2+3x-9$

Therefore, Q - [R + S] is, $4x^2+3x-9$

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