I’m not quite sure but I think it could be c. 768
        
             
        
        
        
The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is 4x²
 
        
        
        
The correct answer for the question that is being presented above is this one: "28 in^2." 
We have to get the individual area of each surface.
A1 = 1*3*2 = 6
A2 = 1*3*2 = 6
A3 = 1*2*2 = 4
A4 = 2*3*2 = 12
Area = A1 + A2 + A3 + A4 
Area = 6 + 6 + 4 + 12
Area = 28 in^2