So... the radiator has 15 liters of 70% antifreeze.. but needs an 80% antifreeze
well, so, you need to drain some and put some with higher percentage, seems to be, you will end up at the same 15 liters, possible the radiator's capacity, of 80% antifreeze
so, the same amount going out, of 70% is the same amount going in, of 100% antifreeze
now.. let's use the decimal format for the percents, or 70% is 70/100 or 0.7 and so on

so.. let's subtract, from the current solution, 0.7x and add 1x or x, our antifreeze concentration amount, should be 12 though
10.5 - 0.7x + x = 12
solve for "x"
I think the answer is 15, because 5 divided by 2 is 2.5. 2.5 times 6 is 15
The property shown in #11 is the Associative Property of Addition.
In short, the associative property of addition states that no matter how an additive expression is grouped, the quantity will turn out the same. In this case, the answer is going to be equal whether you decide to add 5 and 8 first or 8 and 11 first.
Answer:
4 (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is (9 x + 11).
Step-by-step explanation:
Here, given The perimeter of the square = (36 x+44)
Now,as we know :
PERIMETER OF SQUARE = 4 x ( SIDES)
Simplifying the perimeter expression.
Take 4 common out of the expression (36 x+44), we get:
(36 x+44) = 4 (9 x + 11)
⇒ Perimeter of the square = 4 x (9 x + 11)
⇒4 x ( SIDES) = 4 x (9 x + 11)
⇒ Each Side = (9 x + 11)
Hence, 4 x (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is (9 x + 11).
Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000
Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000
Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000