Answer:
0.05 m from the top end
Explanation:
Data provided in the question:
Length of the violin string, λ₁ = 0.45 m
Frequency, f₁ = 392 Hz
New frequency of the violin note, f₂ = 440 Hz
Now,
The velocity of the wave in the string remains constant constant if tension remains constant.
Also,
velocity, v = fλ
thus,
f₁λ₁ = f₂λ₂
392 × 0.45 = 440 × λ₂
or
λ₂ = 0.40 m
thus,
The finger should be placed at (0.45 - 0.40 ) = 0.05 m from the top end
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hope this helps
