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Crank
3 years ago
13

Large wind turbines with a power capacity of 8 MW and blade span diameters of over 160 m are available for electric power genera

tion. Consider a wind turbine with a blade span diameter of 100 m installed at a site subjected to steady winds at 8 m/s. Taking the overall efficiency of the wind turbine to be 34 percent and the air density to be 1.25 kg/m3, determine the electric power generated by this wind turbine. Also, assuming steady winds of 8 m/s during a 24 hour period, determine the amount of electric energy and the revenue generated per day for a unit price of $0.09/kWh for electricity.
Physics
1 answer:
andriy [413]3 years ago
6 0

Answer:

85413.20177 W

2050.831684248 kWh

184.5748512 dollars

Explanation:

d = Diameter of blade = 100 m

r = Radius = \dfrac{d}{2}=\dfrac{100}{2}=50\ m

\eta = Efficiency = 0.34

\rho = Density of air = 1.25 kg/m³

V = Velocity of wind = 8 m/s

A = Area = \pi r^2

The power of a wind turbine is given by

P=\dfrac{1}{2}\rho AV^3\eta\\\Rightarrow P=\dfrac{1}{2}\times 1.25\times \pi\times 50^2\times 8^3\times 0.34\\\Rightarrow P=854513.20177\ W

The power is 85413.20177 W

Energy is given by

E=Pt\\\Rightarrow E=854513.20177\times 24\\\Rightarrow E=20508316.84248\ Wh\\\Rightarrow E=2050.831684248\ kWh

The energy is 2050.831684248 kWh

The revenue is given by

0.09\times 2050.831684248=184.5748512\$

The revenue generated is 184.5748512 dollars

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Answer:

how much space it takes up in the world

Explanation:

1) Mass is a measurement of the amount of matter something contains, while Weight is the measurement of the pull of gravity on an object. 2) Mass is measured by using a balance comparing a known amount of matter to an unknown amount of matter. Weight is measured on a scale.

3 0
3 years ago
Suppose you could fit 100 dimes, end to end, between your card with the pinhole and your dime-sized sunball. how many suns could
Naddika [18.5K]

Answer: 100 suns

Explanation:

We can solve this with the following relation:

\frac{d}{x_{sunball-pinhole}}=\frac{D}{x_{sun-pinhole}}

Where:

d=17.91 mm =17.91(10)^{-3}  m is the diameter of a dime

D is the diameter of the Sun

x_{sun-pinhole}=150,000,000 km=1.5(10)^{11}  m is the distance between the Sun and the pinhole

x_{sunball-pinhole}=100 d=1.791 m is the amount of dimes that fit in a distance between the sunball and the pinhole

Finding D:

D=\frac{d}{x_{sunball-pinhole}}x_{sun-pinhole}

D=\frac{17.91(10)^{-3}  m}{1.791 m} 1.5(10)^{11}  m

D=1.5(10)^{9}  m This is roughly the diameter of the Sun

Now, the distance between the Earth and the Sun is one astronomical unit (1 AU), which is equal to:

1 AU=149,597,870,700 m

So, we have to divide this distance between D in order to find how many suns could it fit in this distance:

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8 0
3 years ago
What is the weight in newtons of a 10 kg mass on the earth's<br> surface?
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Answer:

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Explanation:

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5 0
3 years ago
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It is easier to lift the same load by using three pulley system than by using two-pulley system. why give reason.​
tresset_1 [31]
<h2>QUESTION:- It is easier to lift the same load by using three pulley system than by using two-pulley system.</h2>

<h2>ANSWER:- IN CASE OF IDEAL PULLEY SYSTEM</h2>

<h2>REASON:- </h2>

Logic behind is lies behind the mechanical advantage of the provided bt the Pulley system.

as if we calculate the mechanical advantage of the 2 Pulley system we will have the value 2

And if we will calculate the mechanical advantage of the 3 pulley system then we will get the value of 3

so due to extra mechanical advantage we feel it easy to move with 3 pulley system then 2 Pulley system

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7 0
3 years ago
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lubasha [3.4K]
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2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
I= \frac{V}{R_{eq}}= \frac{12 V}{10.9 \Omega}=1.1 A
4 0
3 years ago
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