Question

What is the internal energy of 3.00 mol of N2 gas at 25 degrees C? To solve this problem, use the equation: U electronic gas = 5/2nRT. Remember that R = 8.31 J/(mol-K) and K = degrees + 273.
A. 37, 100 J
B. 18,600 J
C. 1560 J
D. 623 J

Answer 1

Given data

Determine Internal energy of gas N₂,  (U) = ?

Temperature (T) = 25° C

                          = 25+273 = 298 K,

Gas constant (R) = 8.31 J/ mol-K ,

Number of moles (n) = 3 moles,

Internal energy of N₂

Internal energy is a property of thermodynamics, the concept of internal energy can be understand by ideal gas. For example N₂, the observations for oxygen and nitrogen at atmospheric temperatures,  f=5,  (where f is translational  degrees of freedom).

       So per kilogram of gas,

          The internal energy (U) = 5/2 .n.R.T

                                                  = (5/2) × 3 × 8.31 ×298

                                                  = 18572.85 J

The internal energy of the N₂ is 18,572.85 J and it is approximately equal to 18,600 J given in the option B.

 

Answer 2

Answer: 18,600

Explanation: i just got it right on the test

:DDDDD