Electron;Neutron is the correct answer.
Answer:
speed of each marble after collision will be 1.728 m/sec
Explanation:
We have given mass of the marble
Velocity of marble
Its collides with other marble of mass 25 gram
So mass of other marble
Second marble is at so
We have to find the velocity of second marble
From momentum conservation we know that
, here v is common velocity of both marble after collision
So
v = 1.428 m /sec
So speed of each marble after collision will be 1.728 m/sec
You should note that the melting point of mercury is -38.83°C, while the boiling point is at 356.7°C. Then, that means that there is no latent heat involved here. We only compute for the sensible heat.
ΔH = mCpΔT
The Cp of mercury is 0.14 J/g·°C
Thus,
ΔH = (411 g)(0.14 J/g·°C)(88 - 12°C)
<em>ΔH = 4,373.04 J</em>
Answer:
85.556metres
Explanation:
Using pythagorean theorem
C²=A²+B²
we have c as the hypotenuse vector A thus:
93.8²=A²+38.4²
93.8²-38.4²=A²
8794.44-1474.56=A²
7319.88=A²
A=85.556
One does not simply should you do you should