Answer:Congruence
G-CO.A.1
G-CO.A.2
G-CO.A.3
G-CO.A.4
G-CO.A.5
G-CO.B.6
G-CO.B.7
G-CO.B.8
G-CO.C.9
G-CO.C.10
G-CO.C.11
G-CO.D.12
G-CO.D.13
Similarity, Right Triangles, and Trigonometry
G-SRT.A.1
G-SRT.A.1b
G-SRT.A.2
G-SRT.A.3
G-SRT.B.4
G-SRT.B.5
G-SRT.C.6
G-SRT.C.7
G-SRT.C.8
Circles
G-C.A.1
G-C.A.2
G-C.B.5
Expressing Geometric Properties with
Equations
G-GPE.A.1
G-GPE.B.4
G-GPE.B.5
G-GPE.B.6
G-GPE.B.7
Geometric Measurement and Dimension
G-GMD.A.1
G-GMD.A.3
G-GMD.B.4
Modeling with Geometry
G-MG.A.1
G-MG.A.2
G-MG.A.3
Conditional Proba
Step-by-step explanation: there is the answer
key
Answer:
Step-by-step explanation:
The midline is set on , when the sine function is equal to zero, eliminating the effect from amplitude. The midline is a horizontal line. Hence, the equation of the midline is:
The Given Triangle PMO is a Right Angled Triangle with m∠M = 90°
Given m∠P = 40°
We know that : Sum of Angles in a Triangle = 180°
⇒ m∠P + m∠M + m∠O = 180°
⇒ 40° + 90° + m∠O = 180°
⇒ 130° + m∠O = 180°
⇒ m∠O = 180° - 130°
⇒ m∠O = 50°
We can notice that m∠O and m∠1 form a Linear Pair (180°)
⇒ m∠O + m∠1 = 180°
⇒ 50° + m∠1 = 180°
⇒ m∠1 = 180° - 50°
⇒ m∠1 = 130°
Last Option is the Answer
Answer:
Area of nail's head = 28.26 millimeter² (Approx.)
Step-by-step explanation:
Given:
Head of nail is circular
Diameter of nail's head = 6 millimeter
Find:
Area of nail's head
Computation:
Radius of nail's head = Diameter / 2
Radius of nail's head = 6 / 2
Radius of nail's head = 3 millimeter
Area of circle = πr²
Area of nail's head = πr²
Area of nail's head = (22/7)(3)²
Area of nail's head = (22/7)(9)
Area of nail's head = (3.14)(9)
Area of nail's head = 28.26 millimeter² (Approx.)
Answer:
20 to the 5th power
Step-by-step explanation:
