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Serjik [45]
3 years ago
7

The decay of radioisotopes is a typical first order reaction. The half-life of carbon-14 (14C) is a radioactive isotope that dec

ays to form stable 14N with a half-life of 5,730 yrs. Calculate the time required for 83% 14C to decay to 14N. g
Chemistry
1 answer:
Nady [450]3 years ago
8 0

Answer:

By emitting an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.

Half-life: 5,730 ± 40 years

Names: carbon-14, C-14, radiocarbon

Isotope mass: 14.003241 u

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Explanation:

Given:

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BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

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Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

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