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Ksju [112]
3 years ago
11

What different physical property allows filtration to work?

Chemistry
1 answer:
N76 [4]3 years ago
4 0

Filtration is commonly the mechanical or physical operation which is used for the separation of solids from fluids (liquids or gases) by interposing a medium through which only the fluid can pass. The fluid that passes through is called the filtrate.

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A hydrate of CoCl2with mass of 6.00g heated strongly. After cooling, the mass of anhydrate is 3.27g . How many grams of H2O were
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4 years ago
What is the concentration, in grams per liter, of a solution prepared by dissolving 0.00040 mol HCl in 2.2 L H2O? Assume that th
Zolol [24]

Answer:

0.00663 grams/liter

Explanation:

HCl is a mineral acid with a molar mass of 36.46 g/mol.

No. of moles= mass/RMM

Making mass the subject of the formula:

Mass=Number of moles × RMM

Therefore 0.00040 mol HCl has a mass of:

0.00040 mol × 36.46 g/ mol

=0.01458 grams.

0.01458 grams are in 2.2 liters, Therefore 1 liter will have

0.01458 grams/2.2 liters= 0.00663 grams

concentration= 0.00663 grams/liter

4 0
3 years ago
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Explanation:

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3 years ago
Joe’s cells can’t convert food energy effectively into energy they can use. As a result, he gets extremely tired, has weak legs,
Bad White [126]
The nucleus is effected

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4 years ago
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At what temperature a gas with volume 175 L at 15 oC and 760mmHg will occupy a volume of 198 L at a pressure 640mmHg?
MrRissso [65]

Answer:

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

T

1

P

1

V

1

=

T

2

P

2

V

2

where,

P_1,V_1\text{ and }T_1P

1

,V

1

and T

1

are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2P

2

,V

2

and T

2

are the final pressure, volume and temperature of the gas

We are given:

\begin{gathered}P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K\end{gathered}

P

1

=760mmHg

V

1

=175L

T

1

=15

o

C=[15+273]K=288K

P

2

=640mmHg

V

2

=198L

T

2

=?K

Putting values in above equation, we get:

\begin{gathered}\frac{760mmHg\times 175L}{288K}=\frac{640mmHg\times 198L}{T_2}\\\\T_2=274K\end{gathered}

288K

760mmHg×175L

=

T

2

640mmHg×198L

T

2

=274K

Hence, the temperature when the volume and pressure has changed is 274 K

7 0
3 years ago
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