Answer:
the sum of the squares of the two smaller sides is equal to the square of the third and longer side.
Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.
So we can use formula of perimeter of rectangel to find it's possible dimensions.
We knwo that perimeter of the rectangle is given by 2(L+W)
where L is lenght and W is width.
Given perimeter is 20 so we get:
2(L+W)=20
L+W=10
L=10-W
So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.
Let W=4
Then L=10-W=10-4=6
Hence we just have to draw a rectangle having length 6 and width 4.
So the final answer will be picture in the attached graph.
Answer:
52°
Step-by-step explanation:
(I'm assuming lines JK and HI are parallel)
∠JKA and ∠HIA are corresponding so they are congruent.
Therefore, since ∠JKA is 62, so is ∠HIA. Then knowing the sum of interior angles of a triangle always must be 180, you can just do the math to get 52° as the remaining angle.
66° + 62° + ∠x = 180
∠x = 52°
To be honest i’m probably the worst at math lol good luck
Answer:
32
Step-by-step explanation:
16x2