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AnnyKZ [126]
3 years ago
10

Find the equation of the line parallel to y=4x-10 containing (5,-6)

Mathematics
1 answer:
kogti [31]3 years ago
5 0
Y=mx+b, m=slope, b=y intercept

a line that is paralell will have the same slope with a different y intercept
y=4x-10
therefor the new equation is y=4x+b
subsitute
(x,y)
(5,-6)
x=5
y=-6
is on e solution so subsitue
-6=4(5)+b
-6=20+b
subtract 20
-26=b
the equation si y=4x-26
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Can you guys help we with this question. ​​​​​​
satela [25.4K]

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

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we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

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40

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Read 2 more answers
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