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maria [59]
2 years ago
12

In a 4 3/5 mile race, there are two water stations. The first water station is 1/3 of the way from the starting point. The secon

d water station is 2/3 of the way from the starting point. How far is the first water station to the second water station?
Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

The difference between the first water station and the second would be 1/3 of the total mile distance.

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Can someone help me with the areas?
9966 [12]

Answer:

for 1. it is 99 and for 3. it is 343.75

Step-by-step explanation:

for 1. you have to just multiply the length with width

for 3. you have to add both bases (35+20) and multiply the height (55 x 12.5) to it and then divide it by 2 (687.5 / 2)

hope this helps! please heart <3

8 0
2 years ago
Read 2 more answers
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
Billy charges $15 to mow a yard. He needs at least $200 for the new bicycle that he wants. Write and solve an inequality to find
Marta_Voda [28]
He has to mow 14 yard to get at least 200 but he will have 10 extra dollars.
3 0
3 years ago
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(06.01) In the below system, solve for y in the first equation. x + 3y = 6 2x − y = 10 one thirdx + 2 negative one thirdx + 6 −x
NISA [10]

we have that

x + 3y = 6 -------> first equation

2x − y = 10


x + 3y = 6-----> substract x both sides

-x+x+3y=6-x

3y=6-x-----> divide by 3 both sides

y=(6-x) /3

y=2-(x/3)

y=-(x/3)+2

therefore


the answer is

negative one thirdx + 2

5 0
2 years ago
7th grade math help me plzzzz
Nataly_w [17]

Answer:

<h3>The correct answer is <u>D: -30</u></h3>
5 0
2 years ago
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