The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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Answer: The amount of carbon-14 remaining after 4 years is 99.95 grams.
Step-by-step explanation:
Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.
c= 100 (0.99988)^t
c =100 (0.99988)^4
c = 100 x 0.999520086
c= 99.95200864 ≅99.95 grams (rounded)
The amount of carbon-14 remaining after 4 years is 99.95 grams.
Feel free to ask for more if needed or if you did not understand something.
Answer: b=-12
Step-by-step explanation:
120/-10 = -12
-10b/-10 = b
b=-12
Answer:
A score of 117 is needed, which Is not possible since the test is over 100.
Step-by-step explanation:
The other 3 scores are 85, 94,84 . Let's x be the 4th score he must score.
Therefore ( 85 + 94 + 84 + X)/4 =95
Then 263+X /4 =95
Cross mutiplying 4*95=263+X
Therefore X= 380-263
X= 117 which is not possible since the test score is over 100.
Answer:
The Alans's average for the course is 84.5
Step-by-step explanation:
We are given
There are 4 tests, A Term paper and a Final examination.
Score = 92, 78, 82, 90.
Term paper score = 80
Final examination score = 86
Weighted mean = ∑ w.f/∑w
also the sum of all the weights is 100% = 1
weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1
= 51.3 + 33.2
= 84.5
Therefore the Alans's average for the course is 84.5
