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3 years ago

A snail travels 10 cm in 4 minutes. At this rate:

Mathematics

1 answer:

Elodia [21]3 years ago

4 0

Answer:

Step-by-step explanation:

Find the speed of the snail using this formula;

<em>Speed = Distance/time</em>

Distance= 10cm

time = 4mins

Speed = 10/4 = 2.5 cm/min

Q1.

If 2.5 cm = 1 min

24cm = (24*1) / 2.5 = 9.6 mins or 9mins and 36 seconds.

Q2. Knowing that speed = 2.5cm/min

and time=6 mins, we use the formula; <em>Distance = speed * time;</em>

Distance = 2.5 *6 = 15 cm

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In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

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Step-by-step explanation:

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