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Dmitrij [34]
3 years ago
8

A homeowner measured her rectangular backyard as having a length of 40 yards and a width of 25 yards. Her measurements were accu

rate to the
nearest yard. What is the range of possible values for A, the actual area in square yards of her backyard?
A
936 < A < 1,066
B
967. 75 < A< 1,032.75
с
999 < A< 1,001
D
999.5
Mathematics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:

B.

Step-by-step explanation:

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I need some help with this, I am supposed to solve for x
liq [111]

They are the same measurements, because:

from 10x + 5, first do vertical angle.

then, alternate interior angle,

then vertical angle again,

and another alternate interior angle.

For each vertical and alternate interior angles, the measurements stay the same.


Set them equal to each other, isolate and solve for x.

10x + 5 = 11x - 1

First, isolate the x. Subtract 10x from both sides, and add 1 to both sides

10x (-10x) + 5 (+1) = 11x (-10x) -1 (+1)

Simplify

5 + 1 = 11x - 10x

6 = x

x = 6

6 is your answer for x.

hope this helps

3 0
3 years ago
Elevii clasei a IV-a au fost la patinoar. Stiind ca numarul baietilor reprezinta jumatate plus 3 din numarul copiilor si ca numa
Shalnov [3]

Step-by-step explanation:

Fie x numărul de copii

f = 10 =\:fete

b\:=\:\frac{x}{2}\:+\:3

f\:+\:b\:=\:x

10\:+\:\frac{x}{2}\:+\:3\:=\:x

20\:+\:x\:+\:6\:=\:2x

x\:=\:26\:copii\:au\:fost\:la\:patinoar

b=\frac{26}{2}+\:3

b\:=\:16\:baieti

7 0
2 years ago
ccording to the U.S. National Weather Service, at any given moment of any day, approximately 1000 thunderstorms are occurring wo
viva [34]

Answer:

The critical value of <em>z</em> for 99% confidence interval is 2.5760.

The 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

Step-by-step explanation:

Let <em>X</em> = number of lightning strikes on each day.

A random sample of <em>n</em> = 23 days is selected to observe the number of lightning strikes on each day.

The random variable <em>X</em> has a sample mean of, \bar x=8.1\ mn and the population standard deviation, \sigma=0.51\ mn.

The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Compute the critical value of <em>z</em> for 99% confidence interval is:

z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.5760

*Use a <em>z</em>-table.

The critical value of <em>z</em> for 99% confidence interval is 2.5760.

Compute the 99% confidence interval for population mean number of lightning strike as follows:

CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\=8.1\pm2.5760\times\frac{0.51}{\sqrt{23}}\\=8.1\pm0.2738\\=(7.8262, 8.3738)\\\approx(7.83, 8.37)

Thus, the 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

The 99% confidence interval for population mean number of lightning strike  implies that the true mean number of lightning strikes lies in the interval (7.83 mn, 8.37 mn) with 0.99 probability.

3 0
3 years ago
Solve for x: 0.75x-0.25=3.5
exis [7]

Answer:

x=5

Step-by-step explanation:

3.5=0.75x-0.25

add 0.25 to 3.5

3.75=0.75x

divide 3.75 by 0.75

x=5

4 0
2 years ago
4.b) A strawberry order costs $241.50. How many pounds did the grocer order?​
hram777 [196]
You need more info :/
7 0
3 years ago
Read 2 more answers
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