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Dmitrij [34]
3 years ago
8

A homeowner measured her rectangular backyard as having a length of 40 yards and a width of 25 yards. Her measurements were accu

rate to the
nearest yard. What is the range of possible values for A, the actual area in square yards of her backyard?
A
936 < A < 1,066
B
967. 75 < A< 1,032.75
с
999 < A< 1,001
D
999.5
Mathematics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:

B.

Step-by-step explanation:

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Please could someone help me ?
Marta_Voda [28]

Answer:

Step-by-step explanation:

Sin58 = opp/hyp

Sin58 = CB/14

CB = 14 × sin58°

CB = 11.9cm

8 0
3 years ago
PLS help!!!!!!!!!!!!!!!!!!!!!!!!!!!!
kati45 [8]

The area of the figure is 104.52 sq inches

<h3>How to determine the area of the figure?</h3>

In the complete figure, we have:

1 Rectangle: Base = 8 in and Height = 6 in

2 semicircles: Diameter = 6 inches

The area of the figure is

Area = Area of rectangle + Sum of Areas of semicircles

This gives

Area = Base * Height + 2 * π(d/2)^2

This gives

Area = 8 * 6+ 2 * 3.14 * (6/2)^2

Evaluate

Area = 104.52

Hence, the area of the figure is 104.52 sq inches

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0
2 years ago
Triangle BAC was rotated 90° clockwise and dilated at a scale factor of 2 from the origin to create triangle XYZ. Based on these
ANEK [815]

Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

A(-4, 4), C(-1, 3), B(-4, 0)

The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

8 0
3 years ago
Read 2 more answers
Find the distance between the two points to the nearest tenth. (0,-5) and (-4,2) 5 5.3 5.2 5.6
zubka84 [21]
Sqr (x2 - x1)^2 + (y2 - y1)^2
Sqr (-4-0)^2 + (2+5)^2
Sqr (16) + 49 = sqr 65
I got around 8.
(I might did something wrong, idk)
7 0
3 years ago
(Geometry)<br> Could anyone help me with this please and thanks
Ket [755]

Answer:

z = 32/3

Step-by-step explanation:

Presuming all the horizontal lines are parallel, the ratios of lengths will be identical.

3/8 = 4/z

3z = 8(4)

z = 32/3

8 0
3 years ago
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