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Romashka-Z-Leto [24]
3 years ago
10

Which change in the state of matter is thermal energy released ​

Chemistry
2 answers:
Svet_ta [14]3 years ago
7 0

the state of matter where thermal energy is released is gas..

ycow [4]3 years ago
3 0

Answer:

Condensation

Explanation:

Thermal energy is released in this process

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Calling all chemists...please help me!  Ive attached a screen shot of the problem
Olin [163]
This is an acid-base reaction where HF is the acid and H2O is the base (it's amphoteric and can be an acid or a base). The products would then H3O+ (the conjugate acid) and F- (the conjugate base). Now, we can simply construct a reaction using the found products and reactants. This acid-base reaction would be HF + H2O <--> H3O+ + F-.

Hope this helps!
6 0
3 years ago
Drag the item from the item bank to its corresponding match.
ozzi

Answer:

These are the elements or compounds that enter into a chemical reaction: Reactants

These are the substance(s) formed in a chemical reaction: Products

These are the reactants in the chemical equation C6H1206 +602 --> 6CO2 + 6H20: C6H1206 and 602

These are the reactants in the chemical equation 6 CO2 + 6H2O --> C6H1206 + 6 02: 6 CO2 + 6H2O

These are the reactants in the chemical equation 2 H2 + 02 --> 2 H2O: 2H2 and O2

These are the reactants in the chemical equation 2 H2O --> 2 H2 + O2: 2H2O

4 0
3 years ago
Use the drop-down menus to seled the correct responses to each question about ocean zones
chubhunter [2.5K]

Answer:

Intertidal zone

Neritic zone

Open-ocean zone

Note: the correct questions are found below;

In which zone do you find marshes and mangrove forests?

In which zone are plankton plentiful, providing plenty of food for the fish that live there?

In which zone would you find very little plant or animal life compared to other zones?

Explanation:

The intertidal zone, sometimes called the littoral zone, is the area of the marine shoreline that is exposed to air at low tide, and covered with seawater when the tide is high. Intertidal zonation refers to the tendency of plants and animals to form distinct communities between the high and low tide lines. Some microclimates in the littoral zone are moderated by local features and larger plants such as mangroves.

The neritic zone is the region of shallow water (200 meters depth) above the continental shelf where light penetrates to the sea floor.

Due to the abundant supply of sunlight and nutrients such as plankton in this zone, it is the most productive ocean zone supporting the vast majority of marine life.

The open oceans or pelagic ecosystems are the areas away from the coastal boundaries and above the seabed. It encompasses the entire water column and lies beyond the edge of the continental shelf. It extends from the tropics to the polar regions and from the sea surface to the abyssal depths.

7 0
3 years ago
Read 2 more answers
1
trasher [3.6K]

Answer:

I believe the answer is B

Explanation:

A nucleus of an atom has protons and neutrons. We know that a proton has a charge of +1 , while a neutron has no charge, or 0 . Therefore, the nucleus of an atom will always have a positive charge.

6 0
2 years ago
The AE of a system that releases 12.4 J of heat and does 4.2 J of work on its surroundings It is_______ jA. 16.6 B. 12.4 C. 4.2
andre [41]

ANSWER

EXPLANATION

Given that

The energy released by the system is 12.4J

Work done on the surrounding is 4.2J

Follow the steps below to find the change in energy

In the given data, energy is said to be released to the surroundings

Recall, that exothermic reaction is a type of reaction in which heat is released to the surroundings. Hence, change in enthalpy is negative

Step 1; Write the formula for calculating change in energy

\Delta E\text{ }=\text{ q }+\text{ w}

Since heat is released to the surrounding, then q = -12J

Recall, that work done by the system on the surroundings is always negative

Hence, w = -4.2J

Step 2; Substitute the given data into the formula in step 1

\begin{gathered} \text{  }\Delta E\text{ = q + w} \\ \text{  }\Delta E\text{ }=\text{ -12.4 }+\text{ \lparen-4.2\rparen} \\ \text{  }\Delta E\text{ = -12.4 - 4.2} \\ \text{  }\Delta E\text{ }=\text{ -16.6J} \end{gathered}

Therefore, the change i

3 0
1 year ago
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