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2 years ago

Which change in the state of matter is thermal energy released

Chemistry

2 answers:

Svet_ta [14]2 years ago

7 0

the state of matter where thermal energy is released is gas..

ycow [4]2 years ago

3 0

Answer:

Condensation

Explanation:

Thermal energy is released in this process

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Write a paragraph about the three forms of energy involved in a muscle contraction (chemical, mechanical, and thermal).

klasskru [66]

Chemical energy starts when you eat or drink something bc when you eat or drink something the energy of that food or drink goes into ur muscle.Mechanical occurs when you move ur muscle like when you kick a ball its mechanical.Thermal happens when ur hot or sweating

5 0

2 years ago

Which two processes lead directly to the formation of both breccia and conglomerate

Luden [163]

Compaction and cementation

4 0

3 years ago

Chlorine has two naturally stable isotopes: 35Cl (34.968853 amu) and 37Cl (36.965903 amu). The natural abundance of each isotope

allochka39001 [22]

Answer:

35Cl ⇒ 34.968853 amu has an abundance of 30.05%

Explanation:

The molar mass of chlorine, (which is the average of all its naturally stable isotope masses), is 36.36575 amu.

There are 2 naturally stable isotopes, this means together they have an abundance of 100%

The isotopes are:

35Cl ⇒ 34.968853 amu has an abundance of X %

37Cl ⇒ 36.965903 amu has an abundance of Y %

X + Y = 100% OR X = 100% - Y

36.36575 = 34.968853X + 36.965903Y

36.36575 = 34.968853(1-Y) + 36.936.96590365903Y

36.36575 = 34.968853 -34.968853Y + 36.965903Y

1.396897 = 1.99705Y

Y = 0.699 = 69.95%

X = 100-69.9 = 30.05%

To control, we can plug in the following equation:

34.968853 * 0.3005 + 36.965903 * 0.6995 = 36.3658

This means

37Cl ⇒ 36.965903 amu has an abundance of 69.95 %

35Cl ⇒ 34.968853 amu has an abundance of 30.05%

7 0

3 years ago

Pls help, needed for chemistry

vovangra [49]

Answer:

go to a calculator and see the answer then make the hypothisis which is the answer

Explanation:

magic

7 0

2 years ago

The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =

LuckyWell [14K]

To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

= -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

= -40

8 0

2 years ago

Which change in the state of matter is thermal energy released ​

Which change in the state of matter is thermal energy released