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2 years ago

13

A fecal transplant can work to cure a patient infected with a very harmful bacteria, such as C. difficile.

1 answer:

Dmitrij [34]2 years ago

4 0

Answer: Bacteria from the fecal transplant can fill up the space in the gut, limiting the food and space for invading harmful bacteria.fecal transplants may be best answer to antibiotic-resistant bacteria: Non-pharmaceutical treatment combats recurring Clostridium Difficile infections

Explanation:

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Determine the mechanical energy of this object: a 1-kg ball sits on a 10-meter high cliff.

Bond [772]

Mechanical energy = mass x acceleration due to gravity x height
= 1x9.8x10 = 98J

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3 years ago

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According to the Brensted-Lowry model write the equation for provided acid showing

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A controlled experiment has all variables held constant. <br> a. True <br> b. False

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3 years ago

In a hydrogen molecule, the two hydrogen atoms are held together by a single bond with a bond energy of 436 kj/mol of hydrogen.

svetoff [14.1K]

Answer: 873 kJ of energy will be required to break two moles of hydrogen gas.

$2H_2+O_2\rightarrow 2H_2O$

Above chemical equation shows that two moles of hydrogen gas is reacting with one mole of oxygen gas to give two mole of water molecule.

Bond energy of H-H = 436kJ

According to reaction we have two moles hydrogen,so energy required to break the

H-H bond in two moles of hydrogen gas will be:

$2\times \text{bond energy of H-H bond}$

$2\times {436}$ = 872kJ

872kJ of energy will be required to break H-H bond in two moles of hydrogen gas.

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3 years ago

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Consider the following reaction:2NOBr(g) 2NO(g) + Br2(g)If 0.412 moles of NOBr(g), 0.678 moles of NO, and 0.224 moles of Br2 are

Vaselesa [24]

Answer: $K_c=0.0587M$

Explanation: The given chemical reaction is:

$2NOBr(g)\rightleftharpoons 2NO(g)+Br_2(g)$

Equilibrium constant (Kc) in general is written as:

$K_c=\frac{[products]}{[reactants]}$

Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

$K_c=\frac{[NO]^2[Br_2]}{[NOBr]^2}$

Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.

$[NOBr]=\frac{0.412mol}{10.3L}$ = 0.040 M

$[NO]=\frac{0.678mol}{10.3L}$ = 0.0658 M

$[Br_2]=\frac{0.224mol}{10.3L}$ = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

$K_c=\frac{(0.0658M)^2(0.0217M)}{(0.040M)^2}$

$K_c=0.0587M$

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2 years ago