1) ΔrH = 2mol·ΔfH(NO) - (ΔfH(O₂) + ΔfH(N₂)).
ΔrH = 2 mol · 90.3 kJ/mol - (0 kJ/mol + 0 kJ/mol).
ΔrH = 180.6 kJ.
2) ΔS = 2mol·ΔS(NO) - (ΔS(O₂) + ΔS(N₂)).
ΔS = 2mol · 210.65 J/mol·K - (1mol · 205 J/mol·K + 1 mol · 191.5 J/K·mol).
ΔS = 24.8 J/K.
3) ΔG = ΔH - TΔS.
55°C: ΔG = 180.6 kJ - 328.15 K · 24.8 J/K = 172.46 kJ.
2570°C: ΔG = 180.6 kJ - 2843.15 K · 24.8 J/K = 110.09 kJ.
3610°C: ΔG = 180.6 kJ - 3883.15 K · 24.8 J/K = 84.29 kJ.
We can apply Newton's third law of motion in roller coaster.
Explanation:
- If we are planning to make a roller coaster with elevations and turn then we need to apply newton’s law of motions, kinetic energy and potential energy.
- Newton’s third law of motion says that “ for every action, there is an equal and opposite reaction”. Newton’s third law of motion applies between the tract and ride vehicles.
- If we neglect the air resistance and friction, Roller coaster car will always experience two types of forces which are gravitational force and normal force. The normal force is acting perpendicular to the track and gravitational for is also acting downwards.
- Whenever the tracts get moving the gravitational force is attracting roller coaster to downward. So this will get accelerates. In the majority of the roller coasters, the hill will decrease with height as the train moves along the tract.
Answer:
This question is incomplete
Explanation:
Although, the question above is incomplete, however the correct option can be deduced from the explanation below.
Compounds/chemicals that dissolve in water to conduct electricity are Ionic/electrovalent compounds. Ionic compounds/salts are compounds that are held together by ionic/electrovalent bond. These compounds dissociate in water to form ions; the dissociated ions formed are the carriers of electric charges hence enabling the salt solution conduct electricity. Examples of these electrovalent/ionic compounds include NaCl, CaCl₂, CsF and MgO.
NOTE: Identify the ionic/electrovalent compounds in the options (from the completed question) to get your answer.