Answer:
0.4g
Explanation:
1.0% (w/v%) = 1 g of agarose 100 ml of Tris-Acetate-EDTA, this is the buffer that agarose is run with
the amount of agarose for 40 ml = 1 /100 × 40 ml = 0.4 g
Answer:
17 ppm
Explanation:
Paso 1: Información brindada
Masa de soluto: 0.025 g
Volumen de solución: 1.5 L
Paso 2: Convertir la masa de soluto a miligramos
Usaremos el factor de conversión 1 g = 10³ mg.
0.025 g × (10³ mg/1 g) = 25 mg
Paso 3: Calcular las partes por millon (ppm) del soluto
Usaremos la siguiente expresión.
ppm = mg de soluto / litros de solución
ppm = 25 mg / 1.5 L
ppm = 17 mg/L
Answer:The process is known as sublimation
Explanation:
Sublimation is a process wherby solid substances are changed into gaseous state
<span>A substance has a melting point of 0°c and a boiling point of 100°c the substance is most likely:
</span>A) water