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2 years ago

Chlorine could combine with _ to gain the extra electron it needs to stabilize its outer shell

Chemistry

2 answers:

lana66690 [7]2 years ago

8 0

The correct answer is C hope this helps :)

Ber [7]2 years ago

3 0

Answer:

C, hydrogen.

Explanation:

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Name 3 objects found in the Milky Way galaxy.

dolphi86 [110]

Answer:

The Earth, Stars, and Mars I guess...

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3 years ago

What was the original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44C to 67

zhenek [66]

Answer: 54 atm

Explanation:

I did 67/82.5 then got 0.8121212121. I them divided 44 by 0.81212121 and got 54.1791044776

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3 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

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3 years ago

When NH NO3(aq) reacts to form N2O(g) and H2O(1), 150 kJ of energy are evolved for each mole of NH NO3(aq) that reacts.

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3 years ago

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Citrus2011 [14]

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3 years ago