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Lilit [14]
3 years ago
7

What's the difference between series and parallel circuit in table form?​

Chemistry
2 answers:
schepotkina [342]3 years ago
5 0
Hey :)

In a parallel circuit, a different amount of current flows through each parallel branch of the circuit.

In the series circuit, different voltage exists across each component in the circuit.

Whereas in the parallel circuit, the same voltage exists across the multiple components in the circuit.


Hope this helps :)
tia_tia [17]3 years ago
4 0
When there are two or more electrical devices in a circuit with an energy source, there are a couple of basic ways by which we connect them. They can either be connected in series or parallel. A series circuit is a circuit in which two components share a common node and the same current flows through them. However, in a parallel circuit, components share two common nodes. In this article, let us look at more differences between series and parallel circuit.
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CO(g) + 12 O2(g) → CO2(g)The combustion of carbon monoxide is represented by the equation above.(a) Determine the value of the s
devlian [24]

Answer : The standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The combustion of CO will be,

CO(g)+\frac{1}{2}O_2(g)\rightarrow CO_2(g)    \Delta H_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) C(s)+\frac{1}{2}O_2(g)\rightarrow CO(g)     \Delta H_1=-110.5kJ/mol

(2) C(s)+O_2(g)\rightarrow CO_2(g)     \Delta H_2=-393.5kJ/mol

Now we are reversing reaction 1 and then adding both the equations, we get :

(1) CO(g)\rightarrow C(s)+\frac{1}{2}O_2(g)     \Delta H_1=110.5kJ/mol

(2) C(s)+O_2(g)\rightarrow CO_2(g)     \Delta H_2=-393.5kJ/mol

The expression for enthalpy change for the reaction will be,

\Delta H_{rxn}=\Delta H_1+\Delta H_2

\Delta H_{rxn}=(110.5)+(-393.5)

\Delta H_{rxn}=-283kJ/mol

Therefore, the standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol

6 0
4 years ago
How are the carbon, nitrogen, and oxygen cycles different?
k0ka [10]
The CNO cycle<span> (for </span>carbon–nitrogen–oxygen<span>) is one of the two known sets of fusion reactions by which stars convert hydrogen to helium, the </span>other<span> being the proton–proton chain reaction. Unlike the latter, the CNO </span>cycle<span> is a catalytic </span>cycle<span>.</span>
3 0
3 years ago
Why did scientists in the 1800s decide that the list of known elements needed to be more
ankoles [38]

Explanation:

The scientists realized that the properties of elements related to each other depending on relational properties of their atoms. They realized that atoms of different elements shared some properties depending on the number of electrons they have in their valence orbital shells and atomic mass numbers. These atomic properties determined the elements' shared properties such as texture,  reactivity, electric conductivity and etcetera. Arranging the atoms in a periodic table would therefore ideally make it easier to decipher the shared similarities and differences between atoms of different elements, such as physical and chemical properties.

Learn More:

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8 0
3 years ago
What type(s) of orbital overlap is(are) used to form the indicated bond in the following structure.
lorasvet [3.4K]
D.....................
3 0
2 years ago
Aqueous concentrated nitric acid is 69% hno3 by weight and has a density of 1.42 g/ml.
OleMash [197]

Answer: -

15.55 M

35.325 molal

Explanation: -

Let the volume of the solution be 1000 mL.

Density of nitric acid = 1.42 g/ mL

Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid

= 1000 mL x 1.42 g/ mL

= 1420 g.

Percentage of HNO₃ = 69%

Amount of HNO₃ = \frac{69} {100} x 1420 g

= 979.8 g

Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol

Number of moles of HNO₃ = \frac{979.8 g}{63 g/ mol}

= 15.55 mol

Molarity is defined as number of moles per 1000 mL

We had taken 1000 mL as volume and found it to contain 15.55 moles.

Molarity of HNO₃ = 15.55 M

Mass of water = Total mass of nitric acid solution - mass of nitric acid

= 1420 - 979.8

= 440.2 g

So we see that 440.2 g of water contains 15.55 moles of HNO₃

Molality is defined as number of moles of HNO₃ present per 1000 g of water.

Molality of HNO₃ = \frac{15.55 x 1000}{440.2}

= 35.325 molal

3 0
3 years ago
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