Answer : The standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The combustion of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
Now we are reversing reaction 1 and then adding both the equations, we get :
(1) 
(2)
The expression for enthalpy change for the reaction will be,
Therefore, the standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol
The CNO cycle<span> (for </span>carbon–nitrogen–oxygen<span>) is one of the two known sets of fusion reactions by which stars convert hydrogen to helium, the </span>other<span> being the proton–proton chain reaction. Unlike the latter, the CNO </span>cycle<span> is a catalytic </span>cycle<span>.</span>
Explanation:
The scientists realized that the properties of elements related to each other depending on relational properties of their atoms. They realized that atoms of different elements shared some properties depending on the number of electrons they have in their valence orbital shells and atomic mass numbers. These atomic properties determined the elements' shared properties such as texture, reactivity, electric conductivity and etcetera. Arranging the atoms in a periodic table would therefore ideally make it easier to decipher the shared similarities and differences between atoms of different elements, such as physical and chemical properties.
Learn More:
For more on the periodic table check out these questions;
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Answer: -
15.55 M
35.325 molal
Explanation: -
Let the volume of the solution be 1000 mL.
Density of nitric acid = 1.42 g/ mL
Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid
= 1000 mL x 1.42 g/ mL
= 1420 g.
Percentage of HNO₃ = 69%
Amount of HNO₃ = 
= 979.8 g
Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol
Number of moles of HNO₃ = 
= 15.55 mol
Molarity is defined as number of moles per 1000 mL
We had taken 1000 mL as volume and found it to contain 15.55 moles.
Molarity of HNO₃ = 15.55 M
Mass of water = Total mass of nitric acid solution - mass of nitric acid
= 1420 - 979.8
= 440.2 g
So we see that 440.2 g of water contains 15.55 moles of HNO₃
Molality is defined as number of moles of HNO₃ present per 1000 g of water.
Molality of HNO₃ = 
= 35.325 molal
