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spayn [35]
3 years ago
9

Sue drove her car 253 miles in january, 277 miles in february, and 280 miles in march. if her average mileage for the four month

s from january to april is to be at least 284 miles, how many miles must she drive in april
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0
X= miles driven in April


(253 + 277 + 280 + x)/4= 284
add in parentheses

(810 + x)/4= 284
multiply both sides by 4

810 + x= 1136
subtract 810 from both sides

x= 326 miles


ANSWER: She must drive 326 miles in April to average at least 284 miles January through April.

Hope this helps! :)
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A store sells Brazilian coffee for $10 per lb. and Columbian coffee for $14 per lb. If the store decides to make a 150-lb. blend
Artemon [7]

Answer:

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

Step-by-step explanation:

Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.

Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

b+c=150\\10*b+14*c=11*150

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

b+c=150\\10b+14c -10b-10c=11*150 -(10*150)\\4c=150\\c = 37.5

Now, solve for b by replacing the value obtained into the first equation

b+c=150\\b= 150 - 37.5\\b=112.5

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

6 0
3 years ago
Use the difference of squares identity to write this polynomial expression in factored form:
s344n2d4d5 [400]
9x^2-49
It equals:
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Hope this helps!
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