Question

Enter the equation of the circle described below. Center (3, -2), radius = 5

Answer 1

Answer:

$(x-3)^{2} +(y+2)^{2} =5^{2}$

Step-by-step explanation:

The equation of the circle with center A=(a,b) and radius = r are:

$(x-a)^{2}+(y-b)^{2} =r^{2}$

When A=(3,-2) and radius=r=-5

$(x-3)^{2} +(y+2)^{2} =5^{2}$