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3 years ago

If LM = 5 and MN = 5 what is LN

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

Answer:

LN=10

Step-by-step explanation:

if LM = 5 and MN = 5 then LN=10

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2) Evaluate the given numerical expression. A) 9 B) 12 C) 14 D) 21

eduard

Answer:

$\boxed{\sf{14}}$

Step-by-step explanation:

$\boxed{\underline{\text{ORDER OF OPERATIONS:}}}$

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

PEMDAS

Parentheses
Exponents
Multiply
Divide
Add
Subtract

BODMAS

Brackets
Order
Divide
Add
Subtract

First, do parentheses.

3+6*(5+4)÷3-7

(5+4)=9

$\Longrightarrow: \sf{3+6* 9\div 3-7}$

Do multiply and divide.

6*9=54

54/3=18

Then, rewrite the problem down.

$\Longrightarrow: \sf{3+18-7}$

Add.

$\sf{3+18=21}$

$\sf{21-7=\boxed{\sf{14}}$

$\Longrightarrow: \boxed{\sf{14}}$

Therefore, the correct answer is "C. 14".

I hope this helps, let me know if you have any questions.

8 0

2 years ago

What is the slope of a line that passes through the points (3,0) and (3,2)

Alex787 [66]

Answer:

Step-by-step explanation:

5 0

3 years ago

Factor as the product of two binomials x^2-3x-10

cestrela7 [59]

Answer:

(x-5)(x+2)

Step-by-step explanation:

Hello there!

Your expression there has a highest power of $x^{2}$ , so there will be two constants that you need to find.

Your last term is -10, so the constants will have a product of -10. Also your middle term is -3x, so the terms will add up to -3

-5 and 2 fit the mold.

Have a great day!

If I am most helpful, mark me brainliest!

3 0

3 years ago

Solve the proportional equation below: 5/15 = 3/v

slavikrds [6]

Answer:

Step-by-step explanation:

5/15=3/v

5v=15×3

5v=75

5v/5=75/5

v=15

3 0

3 years ago

Read 2 more answers

When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f

Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

$P(A) = 0.0286 + 0.1*0.9714 = 0.12574$

Probability of you winning and fireworks going off:

100% of 1/35, so $P(A \cap B) = 0.0286$

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275$

0.2275 = 22.75% probability that you actually won that round

8 0

3 years ago