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sasho [114]
4 years ago
15

Suppose that 17 inches of wire costs 51 cents. At the same rate, how much (in cents) will 43 inches of wire cost?

Mathematics
1 answer:
Pavel [41]4 years ago
3 0
Do 43 divided by 17 then you will get 2.5294117647 and multiply it by 51 you will get 129 cents or $1.29
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Write the ratios for sin X, cos X, and tan X. Use the / for a fraction.​
fgiga [73]

Answer:

Step-by-step explanation:

From the right triangle attached in the picture,

sine ratio for the angle X,

\text{sinX}=\frac{\text{Opposite side}}{\text{Hypotenuse}}

       =\frac{YZ}{XZ}

       =\frac{21}{29}

cosine ratio for the angle X,

\text{cosX}=\frac{\text{Adjacent side}}{\text{Hypotenuse}}

        =\frac{XY}{XZ}

        =\frac{20}{29}

tang ratio for the angle X,

\text{tanX}=\frac{\text{Opposite side}}{\text{Adjacent side}}

        =\frac{21}{20}

3 0
3 years ago
Solve and check.
Aleonysh [2.5K]

Answer:

Step-by-step explanation:

-15.4b + 13 = 9b-41.9

-15.4b-9b = -41.9 - 13

-24.4b= -54.9

divide both side by -24.4

-24.4b/-24.4 = -54.9/-24.4

minus divide by (-)

b= 2.25

3 0
3 years ago
A(c + b)=d i need th anwser
Inessa [10]

Answer:

whats the question

6 0
3 years ago
Use the given information to find the p​-value. ​Also, use a 0.05 significance level and state the conclusion about the null hyp
Hatshy [7]

Answer:

We can assume that the statistic is z_{calc}=0.78

p_v = 2* P(z>0.78) = 0.435

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

Step-by-step explanation:

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is equal to 3/5 or not.:  

Null hypothesis:p=3/5  

Alternative hypothesis:p \neq 3/5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

We can assume that the statistic is z_{calc}=0.78

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:

p_v = 2* P(z>0.78) = 0.435

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

7 0
3 years ago
(x+5) •(x-3) using the distributive propertiy
ch4aika [34]

Answer:

the answer for this problem is x^2+2x-15

Step-by-step explanation:

(x+5)(x-3)

x(x-3)+5(x-3)

x^2-3x+5(x-3)

x^2-3x+5x-15

=x^2+2x-15

8 0
3 years ago
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