Answer:
In ΔECB ,
∠ECD = ∠EBC + ∠BEC (∵ Exterior Angle Property of a triangle)
⇒ ∠BEC = ∠ECD - ∠EBC ................. eqn.1
In ΔABC ,
∠ACD = ∠BAC + ∠ABC (∵ Exterior Angle Property of a triangle )
⇒ 2∠ECD = ∠BAC + 2∠EBC
⇒ ∠BAC = 2∠ECD - 2∠EBC = 2(∠ECD - ∠EBC)
( Putting eqn.1 here )
⇒ ∠BAC = 2∠BEC (∵∠BEC = ∠ECD - ∠EBC)
Answer:
g(x) = 3·sin(x + π/2) - 4
Step-by-step explanation:
The given (general form of a) sin function is g(x) = A·sin(x + C) + D
Where;
A = The amplitude (the vertical stretch) = 3
C = The phase shift, left = π/2
D = The vertical shift = 4 units down = -4
Therefore, given that in the parent function, we have f(x) = sin(x), by substituting the values of <em>A</em>, <em>C</em>, and <em>D</em> to complete the equation modeling the function <em>g</em>, we get;
g(x) = 3·sin(x + π/2) - 4
I think that the correct answers are a,d,c
Answer:
6/10 or 6/1/10
Step-by-step explanation:
5 3/5 + 1/3 +1/6 =6/10 or 6/1/10
Answer:
Step-by-step explanation:
This is a 45-45-90 triangle
