Refractory period brief time-out of the heart's electrical impulse that allows for sufficient time for ventricular filling between beats.
<h3>
At what time is the volume of blood in the ventricle at a maximum?</h3>
End-diastolic pressure is at its resting level (end-diastolic pressure) and ventricular volumes are at their maximum value when the heart muscle is relaxed (end-diastolic volume).
What is the state of the heart during systole?
- Describe what occurs during systole in the heart.
- Describe where the blood is sent from each ventricle.
- Right ventricle transfers blood into the pulmonary artery during ventricular contraction and pumps it to the heart.
What are the 4 phases of cardiac cycle?
- There are four main stages of activity in the cardiac cycle: Isovolumic contraction, inflow, ejection, and relaxation are the order of events.
- (See Wiggers graphic, which labels the stages in the following order: 3, 4, 1, and 2, from left to right.)
Learn more about Refractory period
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Answer:
1) ![m=-3\,;\,\, m=\frac{1}{3}](https://tex.z-dn.net/?f=%20m%3D-3%5C%2C%3B%5C%2C%5C%2C%20m%3D%5Cfrac%7B1%7D%7B3%7D)
2) ![m=1\pm\sqrt{6}\\\\](https://tex.z-dn.net/?f=%20m%3D1%5Cpm%5Csqrt%7B6%7D%5C%5C%5C%5C)
Step-by-step explanation:
As differential equation is not give so we consider both equations attached in figure below one by one.
![1) \,3x^{2}\frac{d^2y}{dx^2}+11x\frac{dy}{dx}-3y=0](https://tex.z-dn.net/?f=1%29%20%5C%2C3x%5E%7B2%7D%5Cfrac%7Bd%5E2y%7D%7Bdx%5E2%7D%2B11x%5Cfrac%7Bdy%7D%7Bdx%7D-3y%3D0)
Writing in terms of ∅
![3x^{2}\frac{d^2\phi}{dx^2}+11x\frac{d\phi}{dx}-3\phi=0](https://tex.z-dn.net/?f=3x%5E%7B2%7D%5Cfrac%7Bd%5E2%5Cphi%7D%7Bdx%5E2%7D%2B11x%5Cfrac%7Bd%5Cphi%7D%7Bdx%7D-3%5Cphi%3D0)
Substitute
![\phi=x^m\\\\\phi'=mx^{m-1}\\\\\phi''=m(m-1)x^{m-2}](https://tex.z-dn.net/?f=%5Cphi%3Dx%5Em%5C%5C%5C%5C%5Cphi%27%3Dmx%5E%7Bm-1%7D%5C%5C%5C%5C%5Cphi%27%27%3Dm%28m-1%29x%5E%7Bm-2%7D)
![3x^{2}(m(m-1)x^{m-2})+11x(mx^{m-1})-3x^m=0\\\\3x^{m}(m(m-1))+11mx^{m}-3x^m=0\\\\x^{m}(3m^2-3m+11m-3)=0\\\\3m^2+8m-3=0\\\\By \,\,factorization\\\\3m^2-m+9m-3=0\\\\m(3m-1)+3(3m-1)=0\\\\(m+3)(3m-1)=0\\\\\implies m=-3\,;\,\, m=\frac{1}{3}](https://tex.z-dn.net/?f=3x%5E%7B2%7D%28m%28m-1%29x%5E%7Bm-2%7D%29%2B11x%28mx%5E%7Bm-1%7D%29-3x%5Em%3D0%5C%5C%5C%5C3x%5E%7Bm%7D%28m%28m-1%29%29%2B11mx%5E%7Bm%7D-3x%5Em%3D0%5C%5C%5C%5Cx%5E%7Bm%7D%283m%5E2-3m%2B11m-3%29%3D0%5C%5C%5C%5C3m%5E2%2B8m-3%3D0%5C%5C%5C%5CBy%20%5C%2C%5C%2Cfactorization%5C%5C%5C%5C3m%5E2-m%2B9m-3%3D0%5C%5C%5C%5Cm%283m-1%29%2B3%283m-1%29%3D0%5C%5C%5C%5C%28m%2B3%29%283m-1%29%3D0%5C%5C%5C%5C%5Cimplies%20m%3D-3%5C%2C%3B%5C%2C%5C%2C%20m%3D%5Cfrac%7B1%7D%7B3%7D)
![2)\, x^2\frac{d^2y}{dx^2}-x\frac{dy}{dx}-5y=0---(2)](https://tex.z-dn.net/?f=2%29%5C%2C%20x%5E2%5Cfrac%7Bd%5E2y%7D%7Bdx%5E2%7D-x%5Cfrac%7Bdy%7D%7Bdx%7D-5y%3D0---%282%29)
Writing in terms of ∅
![x^2\frac{d^2\phi}{dx^2}-x\frac{d\phi}{dx}-5\phi=0](https://tex.z-dn.net/?f=x%5E2%5Cfrac%7Bd%5E2%5Cphi%7D%7Bdx%5E2%7D-x%5Cfrac%7Bd%5Cphi%7D%7Bdx%7D-5%5Cphi%3D0)
Substitute
![\phi=x^m\\\\\phi'=mx^{m-1}\\\\\phi''=m(m-1)x^{m-2}](https://tex.z-dn.net/?f=%5Cphi%3Dx%5Em%5C%5C%5C%5C%5Cphi%27%3Dmx%5E%7Bm-1%7D%5C%5C%5C%5C%5Cphi%27%27%3Dm%28m-1%29x%5E%7Bm-2%7D)
![x^2(m(m-1)x^{m-2})-x(mx\phix^{m-1})-5x^{m}=0\\\\(m^2-m)x^m-mx^m-5x^m=0\\\\x^m(m^2-m-m-5)=0\\\\m^2-2m-5=0\\\\Using\,\,quadratic\,\,formula\\\\m=\frac{2\pm \sqrt{20+4}}{2}\\\\m=\frac{2\pm \sqrt{24}}{2}\\\\m=1\pm\sqrt{6}\\\\](https://tex.z-dn.net/?f=x%5E2%28m%28m-1%29x%5E%7Bm-2%7D%29-x%28mx%5Cphix%5E%7Bm-1%7D%29-5x%5E%7Bm%7D%3D0%5C%5C%5C%5C%28m%5E2-m%29x%5Em-mx%5Em-5x%5Em%3D0%5C%5C%5C%5Cx%5Em%28m%5E2-m-m-5%29%3D0%5C%5C%5C%5Cm%5E2-2m-5%3D0%5C%5C%5C%5CUsing%5C%2C%5C%2Cquadratic%5C%2C%5C%2Cformula%5C%5C%5C%5Cm%3D%5Cfrac%7B2%5Cpm%20%5Csqrt%7B20%2B4%7D%7D%7B2%7D%5C%5C%5C%5Cm%3D%5Cfrac%7B2%5Cpm%20%5Csqrt%7B24%7D%7D%7B2%7D%5C%5C%5C%5Cm%3D1%5Cpm%5Csqrt%7B6%7D%5C%5C%5C%5C)
Answer:
480168+988b
Step-by-step explanation:
((22^2)+b)*((32^2)-36) Given
(484+b)(1024-36) Solve for exponents
(486+b)(988) Simplify
480168+988b Simplify
Total albums:
8 + 12 + 4 = 24
Probability of both blue = Probability of first blue x Probability of second blue
P(First blue) = 12/20
P(Second blue) = 11/19
P(Both blue) = 12/20 x 11/19
= 33/95
This can be set up as a proportion to arrive at your final answer of 437,437,437 golf balls