Fractions and whole numbers ordered on the number line are similar because it tells parts throughout the line, like skip counting using adding or subtraction for example.
Whats different from them is because the fractions tell the parts more detailed between the whole numbers, such as 2 3/4 as a fraction on the number line. And 3 as a whole number on the number line.
I will be including both an basic explanation of what it is and its proof.
I'm guessing you are either learning about conditional probability at school or preparing for competitions.
Baye's theorem states:

That is the theorem itself and it means that the probability that event A happens given B is true equals the probability event B happens given A is true times the probability event A happens divided by the probability B happens.
That was the basic of the theorem and the proof of this is basically just testing how well you understand what conditional probability is.


Now we know that the probably that A and B both happens is the same as the probably that B and A both happens.
Therefore P(A|B) can be seen as P(B|A) multiplied by P(A) and then divided by P(B) which gives the right hand side of the first equation. And this is basically the theorem.
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**Note P(B) have to be not equal to 0 because having a 0 in the denominator would make this equation undefined.
If you have any questions or need further explanations please ask me in the comments of the answer, I hope this helped!
Answer:
451.5
Step-by-step explanation:
I'm rusted on the mathematics
The appropriate response is a weighted average. It is a mean ascertained by giving qualities in an informational index more impact as indicated by some characteristic of the information. It is normal in which every amount to have arrived at the midpoint of is allocated a weight, and these weightings decide the relative significance of every amount on the normal.
F(a+h)=2(a+h)³=2(a³+3a²h+3h²a+h³)
the second choice is the correct answer.