Question

Find the 8th term of the geometric sequence show below

Answer 1

Answer:

Alli khanaw .................

Answer 2

Answer:

8x^36

Step-by-step explanation:

first term (a) = $8x^{8}$

Second term (t2)= $8x^{12}$

common ratio (r)

= $\frac{8x^{12} }{8x^{8} }$

= $x^{4}$

now the 8th term of the G.S is

t8 = $ar^{n-1}$

  = $8x^8 * (x^4)^8^-^1$

  = $8x^8 * (x^4)^7$

  = $8x^8 *x^2^8\\= 8x^3^6$

hope it will help