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GenaCL600 [577]
4 years ago
10

What are the dimensions of the product?

Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
8 0

Answer:

<h2>2 x 2</h2>

Step-by-step explanation:

Dimensions: m x n

m = number of rows

n = number of columns

When multiplying two matrices:

m x n *  n x k = m x k

MATIX 1:

m = number of rows

n = number of columns

MATRIX 2:

n = number of rows

k = number of columns

RESULTING MATIX:

m = number of rows

k = number of columns

2 x 3 * 3 x 2 = 2 x 2

Anika [276]4 years ago
7 0

Answer:

The correct option is 2.

Step-by-step explanation:

The given matrix multiplication is

\begin{bmatrix}2&4&-3\\ 6&1&0\end{bmatrix}\times \begin{bmatrix}-3&2\\ -2&3\\ -8&5\end{bmatrix}

Order of matrix = Number of rows × Number of columns

Let A=\begin{bmatrix}2&4&-3\\ 6&1&0\end{bmatrix},B=\begin{bmatrix}-3&2\\ -2&3\\ -8&5\end{bmatrix}

Order of matrix A = 2 × 3

Order of matrix B = 3 × 2

The order of product of two matrices is

A_{m\times n}\cdot B_{n\times k}=AB_{m\times k}

It means

Order of product = Number of rows of first matrix × Number of columns of second matrix

Order of product = 2 × 2

A_{2\times 3}\cdot B_{3\times 2}=AB_{2\times 2}

The dimensions of the product are 2 × 2. Therefore the correct option is 2.

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Answer:

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Then:

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From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

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If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

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Now let's take the maximum value of X in this scenario, this is:

X = AED 40

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3 years ago
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kotykmax [81]

Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Fynjy0 [20]
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