All categories

2 years ago

Find the area of a regular hexagon

Mathematics

1 answer:

xxMikexx [17]2 years ago

4 0

<h2>Answer:</h2><h2>42 cm^2</h2>

please see the attached picture for full solution

hope it helps...

Good luck on your assignment....

You might be interested in

0.1 to 0.2? It's a increase, decrease type thing.

galben [10]

Answer:

its increasing

Step-by-step explanation:

5 0

2 years ago

The table shows how much money Edguardo earns as a golf coach. He charges a flat fee of $38, plus $22 per hour. Complete the tab

Vesnalui [34]

Let's re-read the statement and question, and then break it down.
He charges a flat fee of $38, plus $22 per hour.
A flat fee of $38 is only a one-time pay, and will never be paid for again.
This means if after two hours, we only add $38 once overall, never more.
Every hour that goes by, he earns $22 each hour.
Now that we've broken this down, we can make an equation.
Let's do 1 hour.
1(22) + 38 = 22 + 38, = 60.
For 1 hour he earns $60.
Let's do 2 hours.
2(22) + 38 = 44 + 38, = 82.
For 2 hours he earns $82.
Let's do 3 hours.
3(22) + 38 = 66 + 38, = 104.
For 3 hours he earns $104.
Let's do 4 hours.
4(22) + 38 = 88 + 38, = 126.
For 4 hours he earns $126.
This is a pattern.
Now let's do 8 hours, which is the main question, "How much does he make in 8 hours?".
8(22) + 38 = 176 + 38, = 214.
For 8 hours he earns $214.
I hope this helps!

4 0

3 years ago

Read 2 more answers

Find the output for each input of y = -2x.

Bezzdna [24]

Its the first one because -3(-2)=6, 1(-2)=-2, 2(-2)=4 are all correct

3 0

2 years ago

Read 2 more answers

PHOTO HERE^ help????????

Dmitrij [34]

Please put a thanks so i know your question was answered. It helps since im new here and really boosts my morale :D

if x =4 and y =-3

F = $\frac{ x^{2}-4y }{2} = \frac{ (4)^{2}-4(-3) }{2} = \frac{ 16+12 }{2} = 14$

3 0

3 years ago

I am having trouble with this relative minimum of this equation.

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$