Find the area of a regular hexagon
1 answer:
<h2><em>Answer:</em></h2><h2><em>4</em><em>2</em><em> </em><em>cm^</em><em>2</em></h2>
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>
<em>hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
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Answer:
Step-by-step explanation:
Given : Jennifer got a box of chocolates. the box is a right triangular prism shaped box. it is 7 in long. and the triangular base measure 2in times 3in times 4in.
a = 2
b=3
c=4
To Find : what is the surface area of the box of chocolates?
Solution: The first thing we should know is the area of the triangular base.
Triangular base area:
Where, s is the semi-meter of the triangle:
a, b, c: sides of the triangle.
Substituting:
s = (2 + 3 + 4) /2=4.5
A1 = 2.90
Then, you must know the area of each rectangle associated with each side of the triangular base.
Rectangle area 1: Ar1 = (a) * (l)
Ar1 = (2) * (7)
Ar1 = 14
Rectangular area 2: Ar2 = (b) * (l)
Ar2 = (3) * (7)
Ar2 = 21
Rectangular area 3: Ar3 = (a) * (l)
Ar3 = (4) * (7)
Ar3 = 28
Finally the surface area is: A = Ar1 + Ar2 + Ar3 + 2 * A1
A = (14) + (21) + (28) + 2 * (2.90)
Hence the surface area of the box of chocolates is