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skelet666 [1.2K]
3 years ago
13

William is competing in the shot put event at a track meet. The quadratic expression that models the vertical height of the shot

from the ground, in feet, over the horizontal distance traveled, in feet, x, is given below.
-2x^2+3x+5

What do the zeros of the expression represent?

A.
the initial height from which the shot was thrown
B.
the time it takes for the shot to reach the ground
C.
the maximum height of the shot
D.
the horizontal distance covered by the shot
Mathematics
1 answer:
Tanzania [10]3 years ago
6 0

Answer:

The zero of the equation represents the maximum height attained by the shot put.

Step-by-step explanation:

William is competing in the shot put event at a track meet. The quadratic expression that models the vertical height of the shot from the ground is

H = -2x^{2}+3x+5

We can find the zeroes of these two equations.

For that put H = 0.

-2x^{2}+3x+5 = 0

(-2x + 5)(x + 1) = 0

x= -1 or x = 2.5

x= -1 is neglected as it is not practical.

x = 2.5 is the maximum height attained by the shot put.

The zero of the equation represents the maximum height attained by the shot put.

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Q = (1, -5)

Step-by-step explanation:

Reflection over x-axis (x,y) → (x,-y)

B = (1,5)

Q = (1,-5)

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2 years ago
Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.
dsp73

Answer:

The required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, a_2=10,a_3=5,a_4=2.5,a_5=1.25

r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}

The common ratio of GP is 1/2.

r=\frac{a_2}{a_1}

\frac{1}{2}=\frac{10}{a_1}

a_1=20

The first term of the sequence is 20.

The formula for sequence is

a_n=a(r)^{n-1}

Where a is first term and r is common difference.

The required sequence is

a_n=20(\frac{1}{2})^{n-1}

The formula for rate of change is

m=\frac{f(x_2)-f(x_1)}{x_2-x_1}

The average rate of change from n = 1 to n = 3 is

m=\frac{f(3)-f(1)}{3-1}

m=\frac{5-20}{3-1}

m=\frac{-15}{2}=-7.5

Therefore the required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

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