At a concession stand, three hot dog(s) and two hamburger(s) cost $7.50, two hot dog(s) and three hamburger(s) cost $8.75. Find
1 answer:
Step-by-step explanation:
If 3 HD and 2HB cost $7.50
2 HD and 3HB cost $8.75
Let,y be HD
Y be HB
So 3y + 2x = $7.50. Eqn 1
2y + 3x = $8.75. Eqn 2
Solve simultaneously
Make x the subject in Eqn 1
3y + 2x = 7.50
2x = 7.50 - 3y
Devide by the coefficient of x
2x/2 = (7.50 - 3y) / 2
X = (7.50 - 3y) /2 Eqn 3
Put Eqn 3 into 2
2y + 3(7.50 - 3y) / 2 = 8.75
2y (22.5 - 9y) / 2 =8. 75
Multiply by the lcm of the denominators
2y x 2 + ((22.5 - 9) / 2) x 2 = 8.75 x2
4y + 22.5 - 9y = 17.50
Group like terms
22.5 - 17.50 = 9y - 4y
5 = 5y
5/5 = (5y) / 5
1 = y Eqn 4
Therefore 1 HD is $1
Put Eqn 4 into eqn 3
X = (7. 50 - 3y) / 2
X = (7.50 - 3(1)) / 2
X = 4.5 / 2
X = 2.25
Therefore 1 HB is $2.25
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