Answer:
Usually, the presence of an outlier indicates some sort of problem. This can be a case which does not fit the model under study, or an error in measurement. Outliers are often easy to spot in histograms.
Step-by-step explanation:
It is similar to a Bar Chart, but a histogram groups numbers into ranges
Answer:
0.25% probability that they are both defective
Step-by-step explanation:
For each computer chip, there are only two possible outcomes. Either they are defective, or they are not. The probability of a computer chip being defective is independent of other chips. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
5% of the computer chips it makes are defective.
This means that 
If an inspector chooses two computer chips randomly (meaning they are independent from each other), what is the probability that they are both defective?
This is P(X = 2) when n = 2. So


0.25% probability that they are both defective
1/8 + 1/4
the least common multiple of 8 and 4 is 8. Convert 1/8 and 1/4 to fractions with denominator 8.
1/8 + 2/8
Because 1/8 and 2/8 have the same denominator, add them by adding their numerators.
1+2/8
add 1 and 2 to get 3
3/8 or 0.375
Answer:
Only choices C and D are solutions
Step-by-step explanation:
6x + 3y = -15
y = -2x - 5
6x + 3y = -15
6x + 3(-2x - 5) = -15
6x - 6x - 15 = -15
0 = 0
Since 0 = 0 is a true statement, both equations of this system are the same equation and represent a single line on the coordinate plane.
We need to check each choice in just one equation.
Let's use the second equation.
y = -2x - 5
A.
(2, 7)
7 = -2(2) - 5
7 = -4 - 5
7 = -9 False
Not a solution
B.
(5, 0)
0 = -2(5) - 5
0 = -10 - 5
0 = -15 False
Not a solution
C.
(-3, 1)
1 = -2(-3) - 5
1 = 6 - 5
1 = 1 True
Solution
D.
-13 = -2(4) - 5
-13 = -8 - 5
-13 = -13 True
Solution
Answer: Only choices C and D are solutions