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3 years ago

When the periodic table are the nonmetals located where are the mettalloids?

1 answer:

5 0

Metalloids are the elements found along the stair-step line of the periodic table that distinguishes metals from non metals. The line is drawn from between Boron and Aluminum to the border between Polonium and Astatine. The only exception to this is Aluminum which is classified under "other metals."

Metalloids have properties of both metals and non metals. Some of the metalloids e.g. Silicon and Germanium are semi-conductors. This means they can carry an electrical charge under special conditions and this property makes metalloids very useful in the computer industry.

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18. A simple series circuit has a current of 2 A

QveST [7]

I think it is;
Current = vtotal/requ
2A = vtotal/0.5
2*0.5= vtotal
1=vtotal

5 0

3 years ago

A wire is formed into a circle having a diameter of 19.0 cm and placed in a uniform magnetic field of 3.40 mT. The wire carries

nikklg [1K]

Answer:

Explanation:

Radius = 9.5 x 10⁻² m

area of circle = 3.14 x (9.5 x 10⁻² )²

A = 283.38 x 10⁻⁴ m²

magnetic moment = area x current

M = 283.38 x 10⁻⁴ x 5

= 1416.9 x 10⁻⁴ Am²

Torque = MBsinθ

M is magnetic moment , B is magnetic field .

Max torque = 1416.9 x 10⁻⁴ x 3.4 x 10⁻³ , for θ = 90

= 4817.46 x 10⁻⁷

= 481.7 x 10⁻⁶

= 481.7 μ J

Energy = - MBcosθ

Max energy when θ = 180

MB = 4817.46 x 10⁻⁷ J

Min energy = - 4817.46 x 10⁻⁷ for θ = 0

7 0

3 years ago

A child drops a ball. The ball hits the ground and bounces. The graph to the left shows the velocity-time graph for the ball fro

WINSTONCH [101]

Answer:

Consider the velocity-time graph attached below.

The velocity-time graph represents the acceleration of a body under a force.

We can see that is the graph that if a child release the ball above the ground at A, it hits the ground at B. Bounces back with a reaches the top again at C, and hits the ground again at D.

The slope of velocity time graph represents acceleration. From A to B, velocity in increasing constantly with respect to time, which means constant acceleration from A to B. AS velocity increase, momentum of the ball also increases, which results in the increase of Kinetic energy.

At B, the ball hits the ground, the velocity decreases, momentum decrease s, because kinetic energy is transferred from the ball to the ground, due to which the ball would not attain the same height after the bounce.

Then the velocity remains negative at C, which means that now the ball is moving in opposite direction till C. It reaches its new at height at C, which is not the same as that of A because of lost in Kinetic Energy, and fall again.

4 0

3 years ago

What impulse occurs when an average force of 20-N is applied by a dad to a new bike riding child for 3.5 s. b) What change in mo

garri49 [273]

Answer:

A. 70 Ns

B. 70 Kgm/s

C. 2.19 m/s

Explanation:

A. Determination of the impulse.

Force (F) = 20 N

Time (t) = 3.5 s

Impulse (I) =?

Impulse (I) = force (F) × time (t)

I = Ft

I = 20 × 3.5

I = 70 Ns

Thus, the Impulse is 70 Ns.

B. Determination of the change in momentum

Force (F) = 20 N

Time (t) = 3.5 s

Change in momentum =?

Change in momentum = m(v – u) = Ft

Change in momentum = Ft

Change in momentum = 20 × 3.5

Change in momentum = 70 Kgm/s

C. Determination of the final velocity.

Change in momentum = 70 Kgm/s

Initial velocity (u) = 0 m/s

Combined mass (m) = 32 kg

Final velocity (v) =?

Change in momentum = m(v – u)

70 = 32(v – 0)

70 = 32(v)

70 = 32v

Divide both side by 32

v = 70 / 32

v = 2.19 m/s

Thus, the final velocity is 2.19 m/s

3 0

3 years ago

A traveling electromagnetic wave in a vacuum has an electric field amplitude of 81.1 V/m. Calculate the intensity S of this wave

ICE Princess25 [194]

Answer:

U = 4.39 J

Explanation:

Electric field energy stored in the medium or vacuum is given as

$U = \frac{1}{2}\epsilon_0 E^2 V$

here we know that

$\epsilon_0 = 8.85 \times 10^{-12}$

E = 81.1 V/m

V = volume

$V = (0.0253)(speed \times time)$

$V = (0.0253)(3\times 10^8 \times 19.9)$

$V = 1.51 \times 10^8 m^3$

now from above formula we have

$U = \frac{1}{2}(8.85 \times 10^{-12})(81.1)^2(1.51 \times 10^8)$

$U = 4.39 J$

6 0

4 years ago