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xxMikexx [17]
3 years ago
7

A 21 g bullet is accelerated in a rifle barrel 114 cm long to a speed of 1180 m/s. Use the work-energy theorem to find the avera

ge force exerted on the bullet while it is being accelerated. Answer in units of N.
Physics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

12824.74 N

Explanation:

mass of bullet, m = 21 g = 0.021 kg

distance, s = 114 cm = 1.14 m

final velocity, v = 1180 m/s

initial velocity, u = 0

Let F be the force .

By use of work energy theorem

Work done = change in kinetic energy

F x s = 1/2 m v² - 1/2 mu²

F x 1.14 = 0.5 x 0.021 x 1180 x 1180

F = 12824.74 N

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A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01x10⁵ Pa.
Cerrena [4.2K]

Answer:

\frac{1.019}{1}

Explanation:

To solve this equation we will have to consider that the bubble is filled with an Ideal Gas and as such we can use the Ideal Gas Law

PV = nRT

Where

P = Pressure

V = Volume

n = Moles

R = Ideal Gas Constant

T  = Temperature

Now since we know that the value for the temperature and moles is constant we can simply use Boyles Law for the two states

P_{1} V_{1} =P_{2} V_{2}

Let us look at the two states

State 1 (at top)

Pressure = 1.01*10^5

Volume = V_{1}

State 2 (at bottom)

Pressure = 1.01*10^5 + dgh

Where

d = Density of liquid (1000 kg/m³)

d = Acceleration due to gravity (9.8 m/s²)

d = Height of liquid (0.200 m)

Pressure = 102,962

Volume = V_{2}

Inputting these values into the Boyles Law

P_{1} V_{1} =P_{2} V_{2}\\ (101000)V_{1} = (102962)V_{2}\\ \frac{V_{1}}{V_{2}} = \frac{102962}{101000} \\  \frac{V_{1}}{V_{2}} = \frac{1.019}{1}

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Four radioactive 10-gram (g) samples with their remaining isotope mass are listed in the table that spans 50 years.
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The resolving power of a microscope is proportional to the wavelength used. A resolution of 1.0 10-11 m (0.010 nm) would be requ
Anon25 [30]

Answer:

K = 13448.64eV

Explanation:

(a) In order to calculate the kinetic energy of the electrons, to "see" the atom, you take into account that the wavelength of the electrons must be of the order of the resolution required (0.010nm).

Then, you first calculate, by using the Broglies' relation, the momentum of the electron associated to a wavelength of 0.010nm:

p=\frac{h}{\lambda}       (1)

p: momentum of the electron

h: Planck's constant = 6.626*10^-34 Js

λ: wavelength = 0.010nm

You replace the values of the parameters in the equation (1):

p=\frac{6.262*10^{-34}Js}{0.010*10^{-9}m}=6.262*10^{-23}kg\frac{m}{s}

With this values of the momentum of the electron you can calculate the kinetic energy of the electron by using the following formula:

K=\frac{p^2}{2m}    (2)

m: mass of the electron = 9.1*10^-31 kg

K=\frac{(6.262*10^{-23}kgm/s)^2}{2(9.1*10^{-31}kg)}=2.15*10^{-15 }J

In electron volts you obtain:

2.15*10^{-15}J*\frac{6.242*10^{18}eV}{1J}=13448.64eV

The kinetic energy required for the electrons must be, at least, of 13448.64 eV

5 0
3 years ago
A car travels 200km in the first 2.5 hours of a trip. it stops half am hour and then travels final 200km in 2 hours. find the av
aksik [14]

Answer:

total distance 400km

time 4.5

average speed is 100km

7 0
3 years ago
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