Answer:
(A) Work done will be 87.992 KJ
(B) Work done will be 167.4 KJ            
Explanation:
We have given mass of methane m = 4.5 gram = 0.0045 kg
Volume occupies 
And volume is increased by  so
 so 
Temperature T = 310 K
Pressure is given as 200 Torr = 26664.5 Pa
(a) At constant pressure work done is given by 

(b) At reversible process work done is given by 
We have given mass = 4.5 gram 
Molar mass of methane = 16 
So number of moles 
So work done 
 
        
             
        
        
        
If they lose an electron, that means they become more positive since an electron is negatively charged. So the answer is ‘positive’
        
                    
             
        
        
        
The work done by  along the given path <em>C</em> from <em>A</em> to <em>B</em> is given by the line integral,
 along the given path <em>C</em> from <em>A</em> to <em>B</em> is given by the line integral,

I assume the path itself is a line segment, which can be parameterized by

with 0 ≤ <em>t</em> ≤ 1. Then the work performed by <em>F</em> along <em>C</em> is
![\displaystyle \int_0^1 \left(6x(t)^3\,\vec\imath-4y(t)\,\vec\jmath\right)\cdot\frac{\mathrm d}{\mathrm dt}\left[x(t)\,\vec\imath + y(t)\,\vec\jmath\right]\,\mathrm dt \\\\ = \int_0^1 (288(3t-1)^3-8(2t+5)) \,\mathrm dt = \boxed{312}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E1%20%5Cleft%286x%28t%29%5E3%5C%2C%5Cvec%5Cimath-4y%28t%29%5C%2C%5Cvec%5Cjmath%5Cright%29%5Ccdot%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Bx%28t%29%5C%2C%5Cvec%5Cimath%20%2B%20y%28t%29%5C%2C%5Cvec%5Cjmath%5Cright%5D%5C%2C%5Cmathrm%20dt%20%5C%5C%5C%5C%20%3D%20%5Cint_0%5E1%20%28288%283t-1%29%5E3-8%282t%2B5%29%29%20%5C%2C%5Cmathrm%20dt%20%3D%20%5Cboxed%7B312%7D)
 
        
             
        
        
        
Answer:
E) is described by all of these
Explanation:
The magnetic force on a charged particle is expressed as:
F = qv * B = qvBsinθ
Where, 
q = charge on particle 
θ = angle between the magnetic field and the particle velocity. 
v = velocity of the particle 
B = magnitude of field vector
From here, we could denote that magnetic force, F depends on charge on particle, velocity of particle, magnitude of field vector. 
The magnetic force on a charged particle is at right angles to both the velocity of the particle. The magnetic force and magnetic field in a charged particle are perpendicular to each other, the right hand rule is used to determine the direction of force. 
The correct option is E.