What statement is incorrect about this oxidation-reduction reaction? 2 SO2(g) + O2(g) → 2 SO3(g) What statement is incorrect abo
ut this oxidation-reduction reaction? 2 SO2(g) + O2(g) → 2 SO3(g) SO2 gains electrons. O2 is reduced. SO2 is the reducing agent. O2 is the oxidizing agent.
A chemical reaction that involves the simultaneous transfer of electrons between two chemical species, is known as the redox reaction.
Given chemical reaction: 2SO₂(g) + O₂(g) → 2SO₃(g)
In this redox reaction, S is present in +4 oxidation state in SO₂ and +6 oxidation state SO₃. Whereas, O is present in 0 oxidation state in O₂ and -2 oxidation state in SO₃.
<u>Therefore, SO₂ loses electrons and thus gets oxidized. Whereas, O₂ gains electrons and thus gets reduced. </u>
<u>In this reaction, SO₂ is the reducing agent and O₂ is the oxidizing agent.</u>
1.B 6.D D because t<span>he mass of one mole (molar mass) of helium gas is </span>4.002602 g/mol. 4.002602 * 5=20.01309. Rounded equals 20. So, the answer is D.20 g.
