The gas molecules that make up air are in two rooms. The gas molecules in the kitchen are moving faster than the gas molecules i
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Answer:
Of the following equilibria, only one will shift to the right in response to a decrease in volume.
On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
Decrease the volume
If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. So, the equilibrium will shift in the direction number of gaseous moles are less.
On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.
On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.
On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.
On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.
On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.
<u>Answer:</u> The entropy change of the liquid water is 63.4 J/K
<u>Explanation:</u>
To calculate the entropy change for same phase at different temperature, we use the equation:
where,
= Entropy change
= molar heat capacity of liquid water = 75.38 J/mol.K
n = number of moles of liquid water = 3 moles
= final temperature =
= initial temperature =
Putting values in above equation, we get:
Hence, the entropy change of the liquid water is 63.4 J/K