<span>Percentage of the compound,
silicon = 6.360 %
bromine = 36.18 %
iodine = 57.46 %
In 100 grams of compound we will have
silicon = 6.36, bromine = 36.18, iodine = 57.46
Molar mass
silicon = 28.09, bromine = 79.90, iodine = 126.09
Calculating the moles,
silicon = 6.36 / 28.09 = 0.226
bromine = 36.18 / 79.90 = 0.452
iodine = 57.46 / 126.09 = 0.455
Divide with the lowest
silicon = 0.226 / 0.226 = 1
bromine = 0.452 / 0.226 = 2
iodine = 0.455 / 0.226 = 2
So the empirical formula would be SiBr2I2</span><span />
Answer:
48g of Magnesium.
Explanation:
We know that:
Mole=given mass/molar mass
Then, moles of aluminum = 54/27 = 2.
A/c to question ,
For 2 moles of magnesium it's mass is 2×24=48g.
Hence, the required mass for same number of magnesium atoms is 48g.
(Hope this helps can I pls have brainlist (crown)☺️)
Explanation:
- area of rectangle=l×b
2.area of rectangle=l×b
3. perimeter of square=4×L
4. perimeter of rectangle=2(L+b)
- 14=2(4+b)
- 14=8+2b
- 2b=6
- b=3cm
hope it helps.
