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NikAS [45]
3 years ago
6

PLSSS HELP I AM STUCK ON THIS PROBLEM!!!

Chemistry
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

i can't read it.. maybe upload a visible picture?

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What volume would be occupied by 100. g of oxygen gas at a pressure of 1.50 atm and a temperature of
PSYCHO15rus [73]

Answer:

Use PV = nRT. Don't forget T must be in kelvin.

Explanation:

8 0
3 years ago
How does the number of products in a synthesis reaction compare with the number of reactants?
bearhunter [10]
Its a)the no. of products are greater than the no. of reactants
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Definition of malleable? And example
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Able to be hammered or pressed permanently out of shape without breaking or cracking. An example would be hot metal being shaped.
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Caffeine, a molecule found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 10.0 g of caffeine pr
denis-greek [22]

Answer:

194 g/mol.

Explanation:

Hello,

In this case, one first must compute the mass of each element as shown below:

C=18.13gCO_2*\frac{12gC}{44gCO_2} =4.945gC\\H=4.639gH_2O*\frac{2.016gH}{18.0152gH_2O}=0.519gH\\N=2.885gN_2\\O=10.0g-4.945g-0.519g-2.885g=1.651gO

Next, the corresponding moles:

C=4.945gC*\frac{1molC}{12gC}=0.412mol\\H=0.519gH*\frac{1molH}{1gH}=0.519mol\\N=2.885gN*\frac{1molN}{14gN}=0.206molN\\O=1.648gO*\frac{1molO}{16gO} =0.103molO

Then, each element's subscripts is found to be:

C=\frac{0.412}{0.103}=4\\H=\frac{0.519}{0.103}=5\\N=\frac{0.206}{0.103} =2\\O=\frac{0.103}{0.103}=1

Therefore, the empirical formula is:

C_4H_5N_2O

Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:

C_8H_10N_4O_2

Which has a molar mass of 194 g/mol being correctly contained in the given interval.

Best regards.

8 0
3 years ago
Calculate the frequency of light having wavelength of 456 nm.
Lubov Fominskaja [6]

Answer:

Calculate the frequency of light having wavelength of 456 nm.

1.22*10^8nm

Explanation:

7 0
2 years ago
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