B - No, (4, 8) is not a solution of this provided system of equation.
Reason is quite simple. The following equation is out of the boundaries or "unbounded".
To find out whether this given equation is intended to be in the boundary of those solutions for x = 4 and y = 8. We have to substitute the values of variables of "x" and "y" into the two provided system of equations.
So, just substitute the values of those respective variables to check if it is true or not or whether in the standard given set solution of x, y.



Similarly for our second equation in this system for the provided solution (4, 8).



Therefore, the second statement (B) Satisfies the criteria for this solution set of this system of equations.
Hope it helps.