How would the expression x^2+27 be rewritten using sum of cubes?

1 answer:

6 0

Assuming the square is not a typo, one can write

$x^2+27=(x^{2/3})^3+3^3=(x^{2/3}+3)\bigg((x^{2/3})^2-3x^{2/3}+9\bigg)$

$=(x^{2/3}+3)\bigg(x^{4/3}-3x^{2/3}+9\bigg)$

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