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nydimaria [60]
3 years ago
14

How would the expression x^2+27 be rewritten using sum of cubes?

Mathematics
1 answer:
nydimaria [60]3 years ago
6 0
Assuming the square is not a typo, one can write


x^2+27=(x^{2/3})^3+3^3=(x^{2/3}+3)\bigg((x^{2/3})^2-3x^{2/3}+9\bigg)

=(x^{2/3}+3)\bigg(x^{4/3}-3x^{2/3}+9\bigg)
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Subtract -7n + 2 from 2n - 1.
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Answer:

C) 9n - 3

Step-by-step explanation:

<em>make an expression</em>

2n - 1 - (-7n + 2)

<em>open the parenthesis</em>

2n - 1 + 7n - 2

<em>combine like terms</em>

9n - 3

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3 years ago
Solve using system of equations
IgorC [24]

Answer:

x=8

Step-by-step explanation:

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8 0
3 years ago
suppose that incomes of families in Newport Harbor are normally distributed with a mean of $750,000 and a standard deviation of
denis23 [38]

Answer: 0.345

Step-by-step explanation:

Given : The incomes of families in Newport Harbor are normally distributed with Mean : \mu=\$ 750,000 and Standard deviation : \sigma= $250,000

Samples size : n=4

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The z-statistic :-

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x= $800,000

z=\dfrac{800000-750000}{\dfrac{250000}{\sqrt{4}}}=0.4

By using the standard normal distribution table , we have

The probability that the average income of these 4 families exceeds $800,000 :-

P(x>80,000)=P(z>0.4)=1-P(z\leq0.4)\\\\=1-0.6554217=0.3445783\approx0.345

Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345

6 0
4 years ago
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